1
0
mirror of https://gitee.com/coder-xiaomo/leetcode-problemset synced 2025-01-10 18:48:13 +08:00
Code Issues Projects Releases Wiki Activity GitHub Gitee
leetcode-problemset/leetcode-cn/problem (Chinese)/和可被 K 整除的子数组 [subarray-sums-divisible-by-k].html
2022-03-29 12:43:11 +08:00

33 lines
990 B
HTML
Raw Blame History

This file contains ambiguous Unicode characters

This file contains Unicode characters that might be confused with other characters. If you think that this is intentional, you can safely ignore this warning. Use the Escape button to reveal them.

<p>给定一个整数数组 <code>nums</code>&nbsp;和一个整数 <code>k</code> ,返回其中元素之和可被 <code>k</code>&nbsp;整除的(连续、非空) <strong>子数组</strong> 的数目。</p>
<p><strong>子数组</strong> 是数组的 <strong>连续</strong> 部分。</p>
<p>&nbsp;</p>
<p><strong>示例 1</strong></p>
<pre>
<strong>输入:</strong>nums = [4,5,0,-2,-3,1], k = 5
<strong>输出:</strong>7
<strong>解释:
</strong>有 7 个子数组满足其元素之和可被 k = 5 整除:
[4, 5, 0, -2, -3, 1], [5], [5, 0], [5, 0, -2, -3], [0], [0, -2, -3], [-2, -3]
</pre>
<p><strong>示例 2:</strong></p>
<pre>
<strong>输入:</strong> nums = [5], k = 9
<strong>输出:</strong> 0
</pre>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li><code>1 &lt;= nums.length &lt;= 3 * 10<sup>4</sup></code></li>
<li><code>-10<sup>4</sup>&nbsp;&lt;= nums[i] &lt;= 10<sup>4</sup></code></li>
<li><code>2 &lt;= k &lt;= 10<sup>4</sup></code></li>
</ul>