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28 lines
583 B
HTML
28 lines
583 B
HTML
<p>设计一个算法，找出二叉搜索树中指定节点的“下一个”节点（也即中序后继）。</p>
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<p>如果指定节点没有对应的“下一个”节点，则返回<code>null</code>。</p>
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<p><strong>示例 1:</strong></p>
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<pre><strong>输入:</strong> root = <code>[2,1,3], p = 1
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2
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/ \
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1 3
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</code>
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<strong>输出:</strong> 2</pre>
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<p><strong>示例 2:</strong></p>
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<pre><strong>输入:</strong> root = <code>[5,3,6,2,4,null,null,1], p = 6
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5
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/ \
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3 6
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/ \
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2 4
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/
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1
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</code>
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<strong>输出:</strong> null</pre>
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