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48 lines
2.4 KiB
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<p>按字典 <code>wordList</code> 完成从单词 <code>beginWord</code> 到单词 <code>endWord</code> 转化，一个表示此过程的 <strong>转换序列</strong> 是形式上像 <code>beginWord -> s<sub>1</sub> -> s<sub>2</sub> -> ... -> s<sub>k</sub></code> 这样的单词序列，并满足：</p>
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<div class="original__bRMd">
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<div>
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<ul>
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<li>每对相邻的单词之间仅有单个字母不同。</li>
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<li>转换过程中的每个单词 <code>s<sub>i</sub></code>（<code>1 <= i <= k</code>）必须是字典 <code>wordList</code> 中的单词。注意，<code>beginWord</code> 不必是字典 <code>wordList</code> 中的单词。</li>
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<li><code>s<sub>k</sub> == endWord</code></li>
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</ul>
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<p>给你两个单词 <code>beginWord</code> 和 <code>endWord</code> ，以及一个字典 <code>wordList</code> 。请你找出并返回所有从 <code>beginWord</code> 到 <code>endWord</code> 的 <strong>最短转换序列</strong> ，如果不存在这样的转换序列，返回一个空列表。每个序列都应该以单词列表<em> </em><code>[beginWord, s<sub>1</sub>, s<sub>2</sub>, ..., s<sub>k</sub>]</code> 的形式返回。</p>
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<p> </p>
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<p><strong>示例 1：</strong></p>
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<pre>
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<strong>输入：</strong>beginWord = "hit", endWord = "cog", wordList = ["hot","dot","dog","lot","log","cog"]
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<strong>输出：</strong>[["hit","hot","dot","dog","cog"],["hit","hot","lot","log","cog"]]
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<strong>解释：</strong>存在 2 种最短的转换序列：
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"hit" -> "hot" -> "dot" -> "dog" -> "cog"
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"hit" -> "hot" -> "lot" -> "log" -> "cog"
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</pre>
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<p><strong>示例 2：</strong></p>
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<pre>
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<strong>输入：</strong>beginWord = "hit", endWord = "cog", wordList = ["hot","dot","dog","lot","log"]
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<strong>输出：</strong>[]
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<strong>解释：</strong>endWord "cog" 不在字典 wordList 中，所以不存在符合要求的转换序列。
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</pre>
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<p> </p>
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<p><strong>提示：</strong></p>
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<ul>
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<li><code>1 <= beginWord.length <= 5</code></li>
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<li><code>endWord.length == beginWord.length</code></li>
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<li><code>1 <= wordList.length <= 500</code></li>
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<li><code>wordList[i].length == beginWord.length</code></li>
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<li><code>beginWord</code>、<code>endWord</code> 和 <code>wordList[i]</code> 由小写英文字母组成</li>
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<li><code>beginWord != endWord</code></li>
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<li><code>wordList</code> 中的所有单词 <strong>互不相同</strong></li>
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</ul>
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</div>
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</div>
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