leetcode-problemset/leetcode-cn/originData/maximum-xor-score-subarray-queries.json

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        "question": {
            "questionId": "3551",
            "questionFrontendId": "3277",
            "categoryTitle": "Algorithms",
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            "title": "Maximum XOR Score Subarray Queries",
            "titleSlug": "maximum-xor-score-subarray-queries",
            "content": "<p>You are given an array <code>nums</code> of <code>n</code> integers, and a 2D integer array <code>queries</code> of size <code>q</code>, where <code>queries[i] = [l<sub>i</sub>, r<sub>i</sub>]</code>.</p>\n\n<p>For each query, you must find the <strong>maximum XOR score</strong> of any <span data-keyword=\"subarray\">subarray</span> of <code>nums[l<sub>i</sub>..r<sub>i</sub>]</code>.</p>\n\n<p>The <strong>XOR score</strong> of an array <code>a</code> is found by repeatedly applying the following operations on <code>a</code> so that only one element remains, that is the <strong>score</strong>:</p>\n\n<ul>\n\t<li>Simultaneously replace <code>a[i]</code> with <code>a[i] XOR a[i + 1]</code> for all indices <code>i</code> except the last one.</li>\n\t<li>Remove the last element of <code>a</code>.</li>\n</ul>\n\n<p>Return an array <code>answer</code> of size <code>q</code> where <code>answer[i]</code> is the answer to query <code>i</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [2,8,4,32,16,1], queries = [[0,2],[1,4],[0,5]]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[12,60,60]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>In the first query, <code>nums[0..2]</code> has 6 subarrays <code>[2]</code>, <code>[8]</code>, <code>[4]</code>, <code>[2, 8]</code>, <code>[8, 4]</code>, and <code>[2, 8, 4]</code> each with a respective XOR score of 2, 8, 4, 10, 12, and 6. The answer for the query is 12, the largest of all XOR scores.</p>\n\n<p>In the second query, the subarray of <code>nums[1..4]</code> with the largest XOR score is <code>nums[1..4]</code> with a score of 60.</p>\n\n<p>In the third query, the subarray of <code>nums[0..5]</code> with the largest XOR score is <code>nums[1..4]</code> with a score of 60.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [0,7,3,2,8,5,1], queries = [[0,3],[1,5],[2,4],[2,6],[5,6]]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[7,14,11,14,5]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<table height=\"70\" width=\"472\">\n\t<thead>\n\t\t<tr>\n\t\t\t<th>Index</th>\n\t\t\t<th>nums[l<sub>i</sub>..r<sub>i</sub>]</th>\n\t\t\t<th>Maximum XOR Score Subarray</th>\n\t\t\t<th>Maximum Subarray XOR Score</th>\n\t\t</tr>\n\t</thead>\n\t<tbody>\n\t\t<tr>\n\t\t\t<td>0</td>\n\t\t\t<td>[0, 7, 3, 2]</td>\n\t\t\t<td>[7]</td>\n\t\t\t<td>7</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>1</td>\n\t\t\t<td>[7, 3, 2, 8, 5]</td>\n\t\t\t<td>[7, 3, 2, 8]</td>\n\t\t\t<td>14</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>2</td>\n\t\t\t<td>[3, 2, 8]</td>\n\t\t\t<td>[3, 2, 8]</td>\n\t\t\t<td>11</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>3</td>\n\t\t\t<td>[3, 2, 8, 5, 1]</td>\n\t\t\t<td>[2, 8, 5, 1]</td>\n\t\t\t<td>14</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>4</td>\n\t\t\t<td>[5, 1]</td>\n\t\t\t<td>[5]</td>\n\t\t\t<td>5</td>\n\t\t</tr>\n\t</tbody>\n</table>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == nums.length &lt;= 2000</code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 2<sup>31</sup> - 1</code></li>\n\t<li><code>1 &lt;= q == queries.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>queries[i].length == 2 </code></li>\n\t<li><code>queries[i] = [l<sub>i</sub>, r<sub>i</sub>]</code></li>\n\t<li><code>0 &lt;= l<sub>i</sub> &lt;= r<sub>i</sub> &lt;= n - 1</code></li>\n</ul>\n",
            "translatedTitle": "查询子数组最大异或值",
            "translatedContent": "<p>给你一个由 <code>n</code> 个整数组成的数组 <code>nums</code>，以及一个大小为 <code>q</code> 的二维整数数组 <code>queries</code>，其中 <code>queries[i] = [l<sub>i</sub>, r<sub>i</sub>]</code>。</p>\n\n<p>对于每一个查询，你需要找出 <code>nums[l<sub>i</sub>..r<sub>i</sub>]</code> 中任意 <span data-keyword=\"subarray\">子数组</span> 的 <strong>最大异或值</strong>。</p>\n\n<p><strong>数组的异或值 </strong>需要对数组 <code>a</code> 反复执行以下操作，直到只剩一个元素，剩下的那个元素就是 <strong>异或值</strong>：</p>\n\n<ul>\n\t<li><span class=\"text-only\" data-eleid=\"9\" style=\"white-space: pre;\">对于除最后一个下标以外的所有下标</span> <code>i</code>，同时将 <code>a[i]</code> 替换为 <code>a[i] XOR a[i + 1]</code> 。</li>\n\t<li>移除数组的最后一个元素。</li>\n</ul>\n\n<p>返回一个大小为 <code>q</code> 的数组 <code>answer</code>，其中 <code>answer[i]</code> 表示查询 <code>i</code> 的答案。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">nums = [2,8,4,32,16,1], queries = [[0,2],[1,4],[0,5]]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">[12,60,60]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>在第一个查询中，<code>nums[0..2]</code> 的子数组分别是 <code>[2]</code>, <code>[8]</code>, <code>[4]</code>, <code>[2, 8]</code>, <code>[8, 4]</code>, 和 <code>[2, 8, 4]</code>，它们的异或值分别为 2, 8, 4, 10, 12, 和 6。查询的答案是 12，所有异或值中的最大值。</p>\n\n<p>在第二个查询中，<code>nums[1..4]</code> 的子数组中最大的异或值是子数组 <code>nums[1..4]</code> 的异或值，为 60。</p>\n\n<p>在第三个查询中，<code>nums[0..5]</code> 的子数组中最大的异或值是子数组 <code>nums[1..4]</code> 的异或值，为 60。</p>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">nums = [0,7,3,2,8,5,1], queries = [[0,3],[1,5],[2,4],[2,6],[5,6]]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">[7,14,11,14,5]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<table height=\"70\" width=\"472\">\n\t<thead>\n\t\t<tr>\n\t\t\t<th>下标</th>\n\t\t\t<th>nums[l<sub>i</sub>..r<sub>i</sub>]</th>\n\t\t\t<th>最大异或值子数组</th>\n\t\t\t<th>子数组最大异或值</th>\n\t\t</tr>\n\t</thead>\n\t<tbody>\n\t\t<tr>\n\t\t\t<td>0</td>\n\t\t\t<td>[0, 7, 3, 2]</td>\n\t\t\t<td>[7]</td>\n\t\t\t<td>7</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>1</td>\n\t\t\t<td>[7, 3, 2, 8, 5]</td>\n\t\t\t<td>[7, 3, 2, 8]</td>\n\t\t\t<td>14</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>2</td>\n\t\t\t<td>[3, 2, 8]</td>\n\t\t\t<td>[3, 2, 8]</td>\n\t\t\t<td>11</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>3</td>\n\t\t\t<td>[3, 2, 8, 5, 1]</td>\n\t\t\t<td>[2, 8, 5, 1]</td>\n\t\t\t<td>14</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td>4</td>\n\t\t\t<td>[5, 1]</td>\n\t\t\t<td>[5]</td>\n\t\t\t<td>5</td>\n\t\t</tr>\n\t</tbody>\n</table>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == nums.length &lt;= 2000</code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 2<sup>31</sup> - 1</code></li>\n\t<li><code>1 &lt;= q == queries.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>queries[i].length == 2</code></li>\n\t<li><code>queries[i] = [l<sub>i</sub>, r<sub>i</sub>]</code></li>\n\t<li><code>0 &lt;= l<sub>i</sub> &lt;= r<sub>i</sub> &lt;= n - 1</code></li>\n</ul>\n",
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                "Precompute the XOR score of every subarray.",
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<code>out-of-bounds<\\/code> \\u548c <code>use-after-free<\\/code> \\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 <a href=\\\"https:\\/\\/troydhanson.github.io\\/uthash\\/\\\" target=\\\"_blank\\\">uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n<p><b>1. \\u5f80\\u54c8\\u5e0c\\u8868\\u4e2d\\u6dfb\\u52a0\\u4e00\\u4e2a\\u5bf9\\u8c61\\uff1a<\\/b>\\r\\n<pre>\\r\\nstruct hash_entry {\\r\\n    int id;            \\/* we'll use this field as the key *\\/\\r\\n    char name[10];\\r\\n    UT_hash_handle hh; \\/* makes this structure hashable *\\/\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = 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target=\\\"_blank\\\">\\u300c\\u4ed3\\u9889\\u7f16\\u7a0b\\u8bed\\u8a00\\u5f00\\u53d1\\u6307\\u5357\\u300d<\\/a><\\/p>\"]}",
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