leetcode-problemset/leetcode-cn/originData/timeout-cancellation.json

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            "questionId": "2821",
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            "categoryTitle": "JavaScript",
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            "title": "Timeout Cancellation",
            "titleSlug": "timeout-cancellation",
            "content": "<p>Given a function <code>fn</code>, an array of&nbsp;arguments&nbsp;<code>args</code>, and a timeout&nbsp;<code>t</code>&nbsp;in milliseconds, return a cancel function <code>cancelFn</code>.</p>\n\n<p>After a delay of&nbsp;<code>t</code>,&nbsp;<code>fn</code>&nbsp;should be called with <code>args</code> passed as parameters <strong>unless</strong> <code>cancelFn</code> was invoked before the delay of <code>t</code> milliseconds elapses, specifically at <code>cancelT</code>&nbsp;ms.&nbsp;In that case,&nbsp;<code>fn</code> should never be called.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> fn = (x) =&gt; x * 5, args = [2], t = 20, cancelT = 50\n<strong>Output:</strong> [{&quot;time&quot;: 20, &quot;returned&quot;: 10}]\n<strong>Explanation:</strong> \nconst cancel = cancellable((x) =&gt; x * 5, [2], 20); // fn(2) called at t=20ms\nsetTimeout(cancel, 50);\n\nThe cancellation was scheduled to occur after a delay of cancelT (50ms), which happened after the execution of fn(2) at 20ms.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> fn = (x) =&gt; x**2, args = [2], t = 100, cancelT = 50 \n<strong>Output:</strong> []\n<strong>Explanation:</strong> \nconst cancel = cancellable((x) =&gt; x**2, [2], 100); // fn(2) not called\nsetTimeout(cancel, 50);\n\nThe cancellation was scheduled to occur after a delay of cancelT (50ms), which happened before the execution of fn(2) at 100ms, resulting in fn(2) never being called.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> fn = (x1, x2) =&gt; x1 * x2, args = [2,4], t = 30, cancelT = 100\n<strong>Output:</strong> [{&quot;time&quot;: 30, &quot;returned&quot;: 8}]\n<strong>Explanation:</strong>\nconst cancel = cancellable((x1, x2) =&gt; x1 * x2, [2,4], 30); // fn(2,4) called at t=30ms\nsetTimeout(cancel, 100);\n\nThe cancellation was scheduled to occur after a delay of cancelT (100ms), which happened after the execution of fn(2,4) at 30ms.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>fn is a function</code></li>\n\t<li><code>args is a valid JSON array</code></li>\n\t<li><code>1 &lt;= args.length &lt;= 10</code></li>\n\t<li><code><font face=\"monospace\">20 &lt;= t &lt;= 1000</font></code></li>\n\t<li><code><font face=\"monospace\">10 &lt;= cancelT &lt;= 1000</font></code></li>\n</ul>\n",
            "translatedTitle": "执行可取消的延迟函数",
            "translatedContent": "<p>现给定一个函数 <code>fn</code>&nbsp;，一个参数数组 <code>args</code> 和一个以毫秒为单位的超时时间 <code>t</code> ，返回一个取消函数 <code>cancelFn</code> 。</p>\n\n<p>在经过 <code>t</code> 毫秒的延迟后，应该调用 <code>fn</code> 函数，并将 <code>args</code> 作为参数传递。<strong>除非</strong> 在 <code>t</code> 毫秒的延迟过程中，在 <code>cancelT</code> 毫秒时调用了 <code>cancelFn</code>。并且在这种情况下，<code>fn</code> 函数不应该被调用。</p>\n\n<p><strong class=\"example\">示例 1:</strong></p>\n\n<pre>\n<b>输入：</b>fn = (x) =&gt; x * 5, args = [2], t = 20, cancelT = 50\n<b>输出：</b>[{\"time\": 20, \"returned\": 10}]\n<b>解释：</b>\nconst cancel = cancellable((x) =&gt; x * 5, [2], 20); // fn(2) 在 t=20ms 时被调用\nsetTimeout(cancel, 50);\n\n取消操作被安排在延迟了 cancelT（50毫秒）后进行，这发生在 fn(2) 在20毫秒时执行之后。</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>fn = (x) =&gt; x**2, args = [2], t = 100, cancelT = 50\n<b>输出：</b>[]\n<b>解释：</b>\nconst cancel = cancellable((x) =&gt; x**2, [2], 100); // fn(2) 没被调用\nsetTimeout(cancel, 50);\n\n取消操作被安排在延迟了 cancelT（50毫秒）后进行，这发生在 fn(2) 在100毫秒时执行之前，导致 fn(2) 从未被调用。\n</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<b>输入：</b>fn = (x1, x2) =&gt; x1 * x2, args = [2,4], t = 30, cancelTime = 100\n<b>输出：</b>[{\"time\": 30, \"returned\": 8}]\n<b>解释：</b>\nconst cancel = cancellable((x1, x2) =&gt; x1 * x2, [2,4], 30); // fn(2,4) 在 t=30ms 时被调用\nsetTimeout(cancel, 100);\n\n取消操作被安排在延迟了 cancelT（100毫秒）后进行，这发生在 fn(2,4) 在30毫秒时执行之后。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>fn 是一个函数</code></li>\n\t<li><code>args 是一个有效的 JSON 数组</code></li>\n\t<li><code>1 &lt;= args.length &lt;= 10</code></li>\n\t<li><code><font face=\"monospace\">20 &lt;= t &lt;= 1000</font></code></li>\n\t<li><code><font face=\"monospace\">10 &lt;= cancelT &lt;= 1000</font></code></li>\n</ul>\n",
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                    "code": "function cancellable(fn: Function, args: any[], t: number): Function {\n\n};\n\n/**\n *  const result = []\n *\n *  const fn = (x) => x * 5\n *  const args = [2], t = 20, cancelT = 50\n *\n *  const start = performance.now() \n *\n *  const log = (...argsArr) => {\n *      const diff = Math.floor(performance.now() - start);\n *      result.push({\"time\": diff, \"returned\": fn(...argsArr)})\n *  }\n *       \n *  const cancel = cancellable(log, args, t);\n *\n *  const maxT = Math.max(t, cancelT)\n *           \n *  setTimeout(() => {\n *     cancel()\n *  }, cancelT)\n *\n *  setTimeout(() => {\n *     console.log(result) // [{\"time\":20,\"returned\":10}]\n *  }, maxT + 15)\n */",
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