mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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181 lines
18 KiB
JSON
181 lines
18 KiB
JSON
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"questionId": "2392",
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"title": "Successful Pairs of Spells and Potions",
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"titleSlug": "successful-pairs-of-spells-and-potions",
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"content": "<p>You are given two positive integer arrays <code>spells</code> and <code>potions</code>, of length <code>n</code> and <code>m</code> respectively, where <code>spells[i]</code> represents the strength of the <code>i<sup>th</sup></code> spell and <code>potions[j]</code> represents the strength of the <code>j<sup>th</sup></code> potion.</p>\n\n<p>You are also given an integer <code>success</code>. A spell and potion pair is considered <strong>successful</strong> if the <strong>product</strong> of their strengths is <strong>at least</strong> <code>success</code>.</p>\n\n<p>Return <em>an integer array </em><code>pairs</code><em> of length </em><code>n</code><em> where </em><code>pairs[i]</code><em> is the number of <strong>potions</strong> that will form a successful pair with the </em><code>i<sup>th</sup></code><em> spell.</em></p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> spells = [5,1,3], potions = [1,2,3,4,5], success = 7\n<strong>Output:</strong> [4,0,3]\n<strong>Explanation:</strong>\n- 0<sup>th</sup> spell: 5 * [1,2,3,4,5] = [5,<u><strong>10</strong></u>,<u><strong>15</strong></u>,<u><strong>20</strong></u>,<u><strong>25</strong></u>]. 4 pairs are successful.\n- 1<sup>st</sup> spell: 1 * [1,2,3,4,5] = [1,2,3,4,5]. 0 pairs are successful.\n- 2<sup>nd</sup> spell: 3 * [1,2,3,4,5] = [3,6,<u><strong>9</strong></u>,<u><strong>12</strong></u>,<u><strong>15</strong></u>]. 3 pairs are successful.\nThus, [4,0,3] is returned.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> spells = [3,1,2], potions = [8,5,8], success = 16\n<strong>Output:</strong> [2,0,2]\n<strong>Explanation:</strong>\n- 0<sup>th</sup> spell: 3 * [8,5,8] = [<u><strong>24</strong></u>,15,<u><strong>24</strong></u>]. 2 pairs are successful.\n- 1<sup>st</sup> spell: 1 * [8,5,8] = [8,5,8]. 0 pairs are successful. \n- 2<sup>nd</sup> spell: 2 * [8,5,8] = [<strong><u>16</u></strong>,10,<u><strong>16</strong></u>]. 2 pairs are successful. \nThus, [2,0,2] is returned.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == spells.length</code></li>\n\t<li><code>m == potions.length</code></li>\n\t<li><code>1 <= n, m <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= spells[i], potions[i] <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= success <= 10<sup>10</sup></code></li>\n</ul>\n",
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"difficulty": "Medium",
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"exampleTestcases": "[5,1,3]\n[1,2,3,4,5]\n7\n[3,1,2]\n[8,5,8]\n16",
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"categoryTitle": "Algorithms",
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"code": "class Solution {\npublic:\n vector<int> successfulPairs(vector<int>& spells, vector<int>& potions, long long success) {\n \n }\n};",
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"code": "class Solution(object):\n def successfulPairs(self, spells, potions, success):\n \"\"\"\n :type spells: List[int]\n :type potions: List[int]\n :type success: int\n :rtype: List[int]\n \"\"\"\n ",
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"code": "\n\n/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nint* successfulPairs(int* spells, int spellsSize, int* potions, int potionsSize, long long success, int* returnSize){\n\n}",
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"code": "/**\n * @param {number[]} spells\n * @param {number[]} potions\n * @param {number} success\n * @return {number[]}\n */\nvar successfulPairs = function(spells, potions, success) {\n \n};",
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"code": "# @param {Integer[]} spells\n# @param {Integer[]} potions\n# @param {Integer} success\n# @return {Integer[]}\ndef successful_pairs(spells, potions, success)\n \nend",
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"lang": "Swift",
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"code": "class Solution {\n func successfulPairs(_ spells: [Int], _ potions: [Int], _ success: Int) -> [Int] {\n \n }\n}",
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"lang": "Go",
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"code": "func successfulPairs(spells []int, potions []int, success int64) []int {\n \n}",
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"code": "object Solution {\n def successfulPairs(spells: Array[Int], potions: Array[Int], success: Long): Array[Int] = {\n \n }\n}",
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"code": "class Solution {\n fun successfulPairs(spells: IntArray, potions: IntArray, success: Long): IntArray {\n \n }\n}",
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"lang": "Rust",
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"code": "impl Solution {\n pub fn successful_pairs(spells: Vec<i32>, potions: Vec<i32>, success: i64) -> Vec<i32> {\n \n }\n}",
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"code": "class Solution {\n\n /**\n * @param Integer[] $spells\n * @param Integer[] $potions\n * @param Integer $success\n * @return Integer[]\n */\n function successfulPairs($spells, $potions, $success) {\n \n }\n}",
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"code": "function successfulPairs(spells: number[], potions: number[], success: number): number[] {\n\n};",
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"code": "(define/contract (successful-pairs spells potions success)\n (-> (listof exact-integer?) (listof exact-integer?) exact-integer? (listof exact-integer?))\n\n )",
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"code": "-spec successful_pairs(Spells :: [integer()], Potions :: [integer()], Success :: integer()) -> [integer()].\nsuccessful_pairs(Spells, Potions, Success) ->\n .",
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"code": "defmodule Solution do\n @spec successful_pairs(spells :: [integer], potions :: [integer], success :: integer) :: [integer]\n def successful_pairs(spells, potions, success) do\n\n end\nend",
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"Notice that if a spell and potion pair is successful, then the spell and all stronger potions will be successful too.",
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"Thus, for each spell, we need to find the potion with the least strength that will form a successful pair.",
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"We can efficiently do this by sorting the potions based on strength and using binary search."
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],
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