mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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176 lines
18 KiB
JSON
176 lines
18 KiB
JSON
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"title": "Slowest Key",
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"content": "<p>A newly designed keypad was tested, where a tester pressed a sequence of <code>n</code> keys, one at a time.</p>\n\n<p>You are given a string <code>keysPressed</code> of length <code>n</code>, where <code>keysPressed[i]</code> was the <code>i<sup>th</sup></code> key pressed in the testing sequence, and a sorted list <code>releaseTimes</code>, where <code>releaseTimes[i]</code> was the time the <code>i<sup>th</sup></code> key was released. Both arrays are <strong>0-indexed</strong>. The <code>0<sup>th</sup></code> key was pressed at the time <code>0</code>, and every subsequent key was pressed at the <strong>exact</strong> time the previous key was released.</p>\n\n<p>The tester wants to know the key of the keypress that had the <strong>longest duration</strong>. The <code>i<sup>th</sup></code><sup> </sup>keypress had a <strong>duration</strong> of <code>releaseTimes[i] - releaseTimes[i - 1]</code>, and the <code>0<sup>th</sup></code> keypress had a duration of <code>releaseTimes[0]</code>.</p>\n\n<p>Note that the same key could have been pressed multiple times during the test, and these multiple presses of the same key <strong>may not</strong> have had the same <strong>duration</strong>.</p>\n\n<p><em>Return the key of the keypress that had the <strong>longest duration</strong>. If there are multiple such keypresses, return the lexicographically largest key of the keypresses.</em></p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> releaseTimes = [9,29,49,50], keysPressed = "cbcd"\n<strong>Output:</strong> "c"\n<strong>Explanation:</strong> The keypresses were as follows:\nKeypress for 'c' had a duration of 9 (pressed at time 0 and released at time 9).\nKeypress for 'b' had a duration of 29 - 9 = 20 (pressed at time 9 right after the release of the previous character and released at time 29).\nKeypress for 'c' had a duration of 49 - 29 = 20 (pressed at time 29 right after the release of the previous character and released at time 49).\nKeypress for 'd' had a duration of 50 - 49 = 1 (pressed at time 49 right after the release of the previous character and released at time 50).\nThe longest of these was the keypress for 'b' and the second keypress for 'c', both with duration 20.\n'c' is lexicographically larger than 'b', so the answer is 'c'.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> releaseTimes = [12,23,36,46,62], keysPressed = "spuda"\n<strong>Output:</strong> "a"\n<strong>Explanation:</strong> The keypresses were as follows:\nKeypress for 's' had a duration of 12.\nKeypress for 'p' had a duration of 23 - 12 = 11.\nKeypress for 'u' had a duration of 36 - 23 = 13.\nKeypress for 'd' had a duration of 46 - 36 = 10.\nKeypress for 'a' had a duration of 62 - 46 = 16.\nThe longest of these was the keypress for 'a' with duration 16.</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>releaseTimes.length == n</code></li>\n\t<li><code>keysPressed.length == n</code></li>\n\t<li><code>2 <= n <= 1000</code></li>\n\t<li><code>1 <= releaseTimes[i] <= 10<sup>9</sup></code></li>\n\t<li><code>releaseTimes[i] < releaseTimes[i+1]</code></li>\n\t<li><code>keysPressed</code> contains only lowercase English letters.</li>\n</ul>\n",
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"exampleTestcases": "[9,29,49,50]\n\"cbcd\"\n[12,23,36,46,62]\n\"spuda\"",
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"code": "class Solution(object):\n def slowestKey(self, releaseTimes, keysPressed):\n \"\"\"\n :type releaseTimes: List[int]\n :type keysPressed: str\n :rtype: str\n \"\"\"\n ",
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"code": "impl Solution {\n pub fn slowest_key(release_times: Vec<i32>, keys_pressed: String) -> char {\n \n }\n}",
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"code": "function slowestKey(releaseTimes: number[], keysPressed: string): string {\n\n};",
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"code": "(define/contract (slowest-key releaseTimes keysPressed)\n (-> (listof exact-integer?) string? char?)\n\n )",
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"lang": "Erlang",
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"code": "-spec slowest_key(ReleaseTimes :: [integer()], KeysPressed :: unicode:unicode_binary()) -> char().\nslowest_key(ReleaseTimes, KeysPressed) ->\n .",
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"code": "defmodule Solution do\n @spec slowest_key(release_times :: [integer], keys_pressed :: String.t) :: char\n def slowest_key(release_times, keys_pressed) do\n\n end\nend",
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"hints": [
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"Get for each press its key and amount of time taken.",
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"Iterate on the presses, maintaining the answer so far.",
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"The current press will change the answer if and only if its amount of time taken is longer than that of the previous answer, or they are equal but the key is larger than that of the previous answer."
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