mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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167 lines
16 KiB
JSON
167 lines
16 KiB
JSON
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"question": {
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"questionId": "1078",
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"questionFrontendId": "1021",
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"boundTopicId": null,
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"title": "Remove Outermost Parentheses",
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"titleSlug": "remove-outermost-parentheses",
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"content": "<p>A valid parentheses string is either empty <code>""</code>, <code>"(" + A + ")"</code>, or <code>A + B</code>, where <code>A</code> and <code>B</code> are valid parentheses strings, and <code>+</code> represents string concatenation.</p>\n\n<ul>\n\t<li>For example, <code>""</code>, <code>"()"</code>, <code>"(())()"</code>, and <code>"(()(()))"</code> are all valid parentheses strings.</li>\n</ul>\n\n<p>A valid parentheses string <code>s</code> is primitive if it is nonempty, and there does not exist a way to split it into <code>s = A + B</code>, with <code>A</code> and <code>B</code> nonempty valid parentheses strings.</p>\n\n<p>Given a valid parentheses string <code>s</code>, consider its primitive decomposition: <code>s = P<sub>1</sub> + P<sub>2</sub> + ... + P<sub>k</sub></code>, where <code>P<sub>i</sub></code> are primitive valid parentheses strings.</p>\n\n<p>Return <code>s</code> <em>after removing the outermost parentheses of every primitive string in the primitive decomposition of </em><code>s</code>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "(()())(())"\n<strong>Output:</strong> "()()()"\n<strong>Explanation:</strong> \nThe input string is "(()())(())", with primitive decomposition "(()())" + "(())".\nAfter removing outer parentheses of each part, this is "()()" + "()" = "()()()".\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "(()())(())(()(()))"\n<strong>Output:</strong> "()()()()(())"\n<strong>Explanation:</strong> \nThe input string is "(()())(())(()(()))", with primitive decomposition "(()())" + "(())" + "(()(()))".\nAfter removing outer parentheses of each part, this is "()()" + "()" + "()(())" = "()()()()(())".\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "()()"\n<strong>Output:</strong> ""\n<strong>Explanation:</strong> \nThe input string is "()()", with primitive decomposition "()" + "()".\nAfter removing outer parentheses of each part, this is "" + "" = "".\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 10<sup>5</sup></code></li>\n\t<li><code>s[i]</code> is either <code>'('</code> or <code>')'</code>.</li>\n\t<li><code>s</code> is a valid parentheses string.</li>\n</ul>\n",
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"difficulty": "Easy",
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"exampleTestcases": "\"(()())(())\"\n\"(()())(())(()(()))\"\n\"()()\"",
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"categoryTitle": "Algorithms",
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"lang": "Erlang",
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"code": "-spec remove_outer_parentheses(S :: unicode:unicode_binary()) -> unicode:unicode_binary().\nremove_outer_parentheses(S) ->\n .",
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"code": "defmodule Solution do\n @spec remove_outer_parentheses(s :: String.t) :: String.t\n def remove_outer_parentheses(s) do\n\n end\nend",
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"hints": [
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"Can you find the primitive decomposition? The number of ( and ) characters must be equal."
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],
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"sampleTestCase": "\"(()())(())\"",
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