leetcode-problemset/leetcode/originData/partition-array-according-to-given-pivot.json

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            "title": "Partition Array According to Given Pivot",
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            "content": "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> and an integer <code>pivot</code>. Rearrange <code>nums</code> such that the following conditions are satisfied:</p>\n\n<ul>\n\t<li>Every element less than <code>pivot</code> appears <strong>before</strong> every element greater than <code>pivot</code>.</li>\n\t<li>Every element equal to <code>pivot</code> appears <strong>in between</strong> the elements less than and greater than <code>pivot</code>.</li>\n\t<li>The <strong>relative order</strong> of the elements less than <code>pivot</code> and the elements greater than <code>pivot</code> is maintained.\n\t<ul>\n\t\t<li>More formally, consider every <code>p<sub>i</sub></code>, <code>p<sub>j</sub></code> where <code>p<sub>i</sub></code> is the new position of the <code>i<sup>th</sup></code> element and <code>p<sub>j</sub></code> is the new position of the <code>j<sup>th</sup></code> element. For elements less than <code>pivot</code>, if <code>i &lt; j</code> and <code>nums[i] &lt; pivot</code> and <code>nums[j] &lt; pivot</code>, then <code>p<sub>i</sub> &lt; p<sub>j</sub></code>. Similarly for elements greater than <code>pivot</code>, if <code>i &lt; j</code> and <code>nums[i] &gt; pivot</code> and <code>nums[j] &gt; pivot</code>, then <code>p<sub>i</sub> &lt; p<sub>j</sub></code>.</li>\n\t</ul>\n\t</li>\n</ul>\n\n<p>Return <code>nums</code><em> after the rearrangement.</em></p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [9,12,5,10,14,3,10], pivot = 10\n<strong>Output:</strong> [9,5,3,10,10,12,14]\n<strong>Explanation:</strong> \nThe elements 9, 5, and 3 are less than the pivot so they are on the left side of the array.\nThe elements 12 and 14 are greater than the pivot so they are on the right side of the array.\nThe relative ordering of the elements less than and greater than pivot is also maintained. [9, 5, 3] and [12, 14] are the respective orderings.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [-3,4,3,2], pivot = 2\n<strong>Output:</strong> [-3,2,4,3]\n<strong>Explanation:</strong> \nThe element -3 is less than the pivot so it is on the left side of the array.\nThe elements 4 and 3 are greater than the pivot so they are on the right side of the array.\nThe relative ordering of the elements less than and greater than pivot is also maintained. [-3] and [4, 3] are the respective orderings.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>6</sup> &lt;= nums[i] &lt;= 10<sup>6</sup></code></li>\n\t<li><code>pivot</code> equals to an element of <code>nums</code>.</li>\n</ul>\n",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    vector<int> pivotArray(vector<int>& nums, int pivot) {\n        \n    }\n};",
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                    "lang": "Java",
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                    "code": "class Solution {\n    public int[] pivotArray(int[] nums, int pivot) {\n        \n    }\n}",
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                    "lang": "Python",
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                    "code": "class Solution(object):\n    def pivotArray(self, nums, pivot):\n        \"\"\"\n        :type nums: List[int]\n        :type pivot: int\n        :rtype: List[int]\n        \"\"\"\n        ",
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                    "lang": "Python3",
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                    "code": "class Solution:\n    def pivotArray(self, nums: List[int], pivot: int) -> List[int]:\n        ",
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                    "lang": "C",
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                    "code": "\n\n/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nint* pivotArray(int* nums, int numsSize, int pivot, int* returnSize){\n\n}",
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                    "lang": "C#",
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                    "code": "public class Solution {\n    public int[] PivotArray(int[] nums, int pivot) {\n        \n    }\n}",
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                    "lang": "JavaScript",
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                    "code": "/**\n * @param {number[]} nums\n * @param {number} pivot\n * @return {number[]}\n */\nvar pivotArray = function(nums, pivot) {\n    \n};",
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                    "lang": "Ruby",
                    "langSlug": "ruby",
                    "code": "# @param {Integer[]} nums\n# @param {Integer} pivot\n# @return {Integer[]}\ndef pivot_array(nums, pivot)\n    \nend",
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                    "lang": "Swift",
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                    "code": "class Solution {\n    func pivotArray(_ nums: [Int], _ pivot: Int) -> [Int] {\n        \n    }\n}",
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                    "lang": "Go",
                    "langSlug": "golang",
                    "code": "func pivotArray(nums []int, pivot int) []int {\n    \n}",
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                    "lang": "Scala",
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                    "code": "object Solution {\n    def pivotArray(nums: Array[Int], pivot: Int): Array[Int] = {\n        \n    }\n}",
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                    "lang": "Kotlin",
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                    "code": "class Solution {\n    fun pivotArray(nums: IntArray, pivot: Int): IntArray {\n        \n    }\n}",
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                    "lang": "Rust",
                    "langSlug": "rust",
                    "code": "impl Solution {\n    pub fn pivot_array(nums: Vec<i32>, pivot: i32) -> Vec<i32> {\n        \n    }\n}",
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                    "lang": "PHP",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer[] $nums\n     * @param Integer $pivot\n     * @return Integer[]\n     */\n    function pivotArray($nums, $pivot) {\n        \n    }\n}",
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                    "code": "function pivotArray(nums: number[], pivot: number): number[] {\n\n};",
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                    "code": "(define/contract (pivot-array nums pivot)\n  (-> (listof exact-integer?) exact-integer? (listof exact-integer?))\n\n  )",
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                    "lang": "Erlang",
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                    "code": "-spec pivot_array(Nums :: [integer()], Pivot :: integer()) -> [integer()].\npivot_array(Nums, Pivot) ->\n  .",
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                    "lang": "Elixir",
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                    "code": "defmodule Solution do\n  @spec pivot_array(nums :: [integer], pivot :: integer) :: [integer]\n  def pivot_array(nums, pivot) do\n\n  end\nend",
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            "hints": [
                "Could you put the elements smaller than the pivot and greater than the pivot in a separate list as in the sequence that they occur?",
                "With the separate lists generated, could you then generate the result?"
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