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"title": "Palindrome Partitioning IV",
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"content": "<p>Given a string <code>s</code>, return <code>true</code> <em>if it is possible to split the string</em> <code>s</code> <em>into three <strong>non-empty</strong> palindromic substrings. Otherwise, return </em><code>false</code>.</p>\n\n<p>A string is said to be palindrome if it the same string when reversed.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;abcbdd&quot;\n<strong>Output:</strong> true\n<strong>Explanation: </strong>&quot;abcbdd&quot; = &quot;a&quot; + &quot;bcb&quot; + &quot;dd&quot;, and all three substrings are palindromes.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;bcbddxy&quot;\n<strong>Output:</strong> false\n<strong>Explanation: </strong>s cannot be split into 3 palindromes.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>3 &lt;= s.length &lt;= 2000</code></li>\n\t<li><code>s</code> consists only of lowercase English letters.</li>\n</ul>\n",
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"hints": [
"Preprocess checking palindromes in O(1)",
"Note that one string is a prefix and another one is a suffix you can try brute forcing the rest"
],
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