mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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192 lines
18 KiB
JSON
192 lines
18 KiB
JSON
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"questionId": "744",
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"title": "Network Delay Time",
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"content": "<p>You are given a network of <code>n</code> nodes, labeled from <code>1</code> to <code>n</code>. You are also given <code>times</code>, a list of travel times as directed edges <code>times[i] = (u<sub>i</sub>, v<sub>i</sub>, w<sub>i</sub>)</code>, where <code>u<sub>i</sub></code> is the source node, <code>v<sub>i</sub></code> is the target node, and <code>w<sub>i</sub></code> is the time it takes for a signal to travel from source to target.</p>\n\n<p>We will send a signal from a given node <code>k</code>. Return the time it takes for all the <code>n</code> nodes to receive the signal. If it is impossible for all the <code>n</code> nodes to receive the signal, return <code>-1</code>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/05/23/931_example_1.png\" style=\"width: 217px; height: 239px;\" />\n<pre>\n<strong>Input:</strong> times = [[2,1,1],[2,3,1],[3,4,1]], n = 4, k = 2\n<strong>Output:</strong> 2\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> times = [[1,2,1]], n = 2, k = 1\n<strong>Output:</strong> 1\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> times = [[1,2,1]], n = 2, k = 2\n<strong>Output:</strong> -1\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= k <= n <= 100</code></li>\n\t<li><code>1 <= times.length <= 6000</code></li>\n\t<li><code>times[i].length == 3</code></li>\n\t<li><code>1 <= u<sub>i</sub>, v<sub>i</sub> <= n</code></li>\n\t<li><code>u<sub>i</sub> != v<sub>i</sub></code></li>\n\t<li><code>0 <= w<sub>i</sub> <= 100</code></li>\n\t<li>All the pairs <code>(u<sub>i</sub>, v<sub>i</sub>)</code> are <strong>unique</strong>. (i.e., no multiple edges.)</li>\n</ul>\n",
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"categoryTitle": "Algorithms",
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"code": "class Solution(object):\n def networkDelayTime(self, times, n, k):\n \"\"\"\n :type times: List[List[int]]\n :type n: int\n :type k: int\n :rtype: int\n \"\"\"\n ",
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"code": "# @param {Integer[][]} times\n# @param {Integer} n\n# @param {Integer} k\n# @return {Integer}\ndef network_delay_time(times, n, k)\n \nend",
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"code": "object Solution {\n def networkDelayTime(times: Array[Array[Int]], n: Int, k: Int): Int = {\n \n }\n}",
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"code": "class Solution {\n fun networkDelayTime(times: Array<IntArray>, n: Int, k: Int): Int {\n \n }\n}",
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"code": "impl Solution {\n pub fn network_delay_time(times: Vec<Vec<i32>>, n: i32, k: i32) -> i32 {\n \n }\n}",
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"code": "class Solution {\n\n /**\n * @param Integer[][] $times\n * @param Integer $n\n * @param Integer $k\n * @return Integer\n */\n function networkDelayTime($times, $n, $k) {\n \n }\n}",
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"code": "defmodule Solution do\n @spec network_delay_time(times :: [[integer]], n :: integer, k :: integer) :: integer\n def network_delay_time(times, n, k) do\n\n end\nend",
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"We visit each node at some time, and if that time is better than the fastest time we've reached this node, we travel along outgoing edges in sorted order. Alternatively, we could use Dijkstra's algorithm."
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