mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
193 lines
17 KiB
JSON
193 lines
17 KiB
JSON
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"title": "Contains Duplicate III",
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"content": "<p>Given an integer array <code>nums</code> and two integers <code>k</code> and <code>t</code>, return <code>true</code> if there are <strong>two distinct indices</strong> <code>i</code> and <code>j</code> in the array such that <code>abs(nums[i] - nums[j]) <= t</code> and <code>abs(i - j) <= k</code>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n<pre><strong>Input:</strong> nums = [1,2,3,1], k = 3, t = 0\n<strong>Output:</strong> true\n</pre><p><strong>Example 2:</strong></p>\n<pre><strong>Input:</strong> nums = [1,0,1,1], k = 1, t = 2\n<strong>Output:</strong> true\n</pre><p><strong>Example 3:</strong></p>\n<pre><strong>Input:</strong> nums = [1,5,9,1,5,9], k = 2, t = 3\n<strong>Output:</strong> false\n</pre>\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 2 * 10<sup>4</sup></code></li>\n\t<li><code>-2<sup>31</sup> <= nums[i] <= 2<sup>31</sup> - 1</code></li>\n\t<li><code>0 <= k <= 10<sup>4</sup></code></li>\n\t<li><code>0 <= t <= 2<sup>31</sup> - 1</code></li>\n</ul>\n",
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"code": "# @param {Integer[]} nums\n# @param {Integer} k\n# @param {Integer} t\n# @return {Boolean}\ndef contains_nearby_almost_duplicate(nums, k, t)\n \nend",
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"code": "class Solution {\n\n /**\n * @param Integer[] $nums\n * @param Integer $k\n * @param Integer $t\n * @return Boolean\n */\n function containsNearbyAlmostDuplicate($nums, $k, $t) {\n \n }\n}",
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"code": "(define/contract (contains-nearby-almost-duplicate nums k t)\n (-> (listof exact-integer?) exact-integer? exact-integer? boolean?)\n\n )",
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"Time complexity O(n logk) - This will give an indication that sorting is involved for k elements.",
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"Use already existing state to evaluate next state - Like, a set of k sorted numbers are only needed to be tracked. When we are processing the next number in array, then we can utilize the existing sorted state and it is not necessary to sort next overlapping set of k numbers again."
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