mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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174 lines
22 KiB
JSON
174 lines
22 KiB
JSON
{
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"data": {
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"question": {
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"questionId": "1248",
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"questionFrontendId": "1145",
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"boundTopicId": null,
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"title": "Binary Tree Coloring Game",
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"titleSlug": "binary-tree-coloring-game",
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"content": "<p>Two players play a turn based game on a binary tree. We are given the <code>root</code> of this binary tree, and the number of nodes <code>n</code> in the tree. <code>n</code> is odd, and each node has a distinct value from <code>1</code> to <code>n</code>.</p>\n\n<p>Initially, the first player names a value <code>x</code> with <code>1 <= x <= n</code>, and the second player names a value <code>y</code> with <code>1 <= y <= n</code> and <code>y != x</code>. The first player colors the node with value <code>x</code> red, and the second player colors the node with value <code>y</code> blue.</p>\n\n<p>Then, the players take turns starting with the first player. In each turn, that player chooses a node of their color (red if player 1, blue if player 2) and colors an <strong>uncolored</strong> neighbor of the chosen node (either the left child, right child, or parent of the chosen node.)</p>\n\n<p>If (and only if) a player cannot choose such a node in this way, they must pass their turn. If both players pass their turn, the game ends, and the winner is the player that colored more nodes.</p>\n\n<p>You are the second player. If it is possible to choose such a <code>y</code> to ensure you win the game, return <code>true</code>. If it is not possible, return <code>false</code>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/08/01/1480-binary-tree-coloring-game.png\" style=\"width: 500px; height: 310px;\" />\n<pre>\n<strong>Input:</strong> root = [1,2,3,4,5,6,7,8,9,10,11], n = 11, x = 3\n<strong>Output:</strong> true\n<strong>Explanation: </strong>The second player can choose the node with value 2.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> root = [1,2,3], n = 3, x = 1\n<strong>Output:</strong> false\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is <code>n</code>.</li>\n\t<li><code>1 <= x <= n <= 100</code></li>\n\t<li><code>n</code> is odd.</li>\n\t<li>1 <= Node.val <= n</li>\n\t<li>All the values of the tree are <strong>unique</strong>.</li>\n</ul>\n",
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"translatedTitle": null,
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"isPaidOnly": false,
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"difficulty": "Medium",
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"likes": 952,
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"dislikes": 172,
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"similarQuestions": "[]",
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"exampleTestcases": "[1,2,3,4,5,6,7,8,9,10,11]\n11\n3\n[1,2,3]\n3\n1",
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"categoryTitle": "Algorithms",
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"contributors": [],
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"topicTags": [
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{
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"name": "Tree",
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"slug": "tree",
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"translatedName": null,
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"__typename": "TopicTagNode"
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},
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{
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"name": "Depth-First Search",
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"slug": "depth-first-search",
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"translatedName": null,
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"__typename": "TopicTagNode"
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},
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{
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"name": "Binary Tree",
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"slug": "binary-tree",
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"lang": "C++",
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"langSlug": "cpp",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode() : val(0), left(nullptr), right(nullptr) {}\n * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n bool btreeGameWinningMove(TreeNode* root, int n, int x) {\n \n }\n};",
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"lang": "Java",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * int val;\n * TreeNode left;\n * TreeNode right;\n * TreeNode() {}\n * TreeNode(int val) { this.val = val; }\n * TreeNode(int val, TreeNode left, TreeNode right) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\nclass Solution {\n public boolean btreeGameWinningMove(TreeNode root, int n, int x) {\n \n }\n}",
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{
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"lang": "Python",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution(object):\n def btreeGameWinningMove(self, root, n, x):\n \"\"\"\n :type root: TreeNode\n :type n: int\n :type x: int\n :rtype: bool\n \"\"\"\n ",
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"lang": "Python3",
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"langSlug": "python3",
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"code": "# Definition for a binary tree node.\n# class TreeNode:\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution:\n def btreeGameWinningMove(self, root: Optional[TreeNode], n: int, x: int) -> bool:\n ",
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"__typename": "CodeSnippetNode"
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},
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{
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"lang": "C",
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"langSlug": "c",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * struct TreeNode *left;\n * struct TreeNode *right;\n * };\n */\n\n\nbool btreeGameWinningMove(struct TreeNode* root, int n, int x){\n\n}",
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"lang": "C#",
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"langSlug": "csharp",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public bool BtreeGameWinningMove(TreeNode root, int n, int x) {\n \n }\n}",
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"__typename": "CodeSnippetNode"
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},
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{
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"lang": "JavaScript",
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"langSlug": "javascript",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @param {number} n\n * @param {number} x\n * @return {boolean}\n */\nvar btreeGameWinningMove = function(root, n, x) {\n \n};",
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"__typename": "CodeSnippetNode"
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},
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{
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"lang": "Ruby",
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"langSlug": "ruby",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @param {Integer} n\n# @param {Integer} x\n# @return {Boolean}\ndef btree_game_winning_move(root, n, x)\n \nend",
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"__typename": "CodeSnippetNode"
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{
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"lang": "Swift",
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"langSlug": "swift",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func btreeGameWinningMove(_ root: TreeNode?, _ n: Int, _ x: Int) -> Bool {\n \n }\n}",
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"__typename": "CodeSnippetNode"
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},
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{
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"lang": "Go",
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"langSlug": "golang",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc btreeGameWinningMove(root *TreeNode, n int, x int) bool {\n \n}",
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{
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"lang": "Scala",
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"langSlug": "scala",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def btreeGameWinningMove(root: TreeNode, n: Int, x: Int): Boolean = {\n \n }\n}",
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"__typename": "CodeSnippetNode"
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},
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{
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"lang": "Kotlin",
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"langSlug": "kotlin",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun btreeGameWinningMove(root: TreeNode?, n: Int, x: Int): Boolean {\n \n }\n}",
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{
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"lang": "Rust",
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"langSlug": "rust",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n// \n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn btree_game_winning_move(root: Option<Rc<RefCell<TreeNode>>>, n: i32, x: i32) -> bool {\n \n }\n}",
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"__typename": "CodeSnippetNode"
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"lang": "PHP",
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"langSlug": "php",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @param Integer $n\n * @param Integer $x\n * @return Boolean\n */\n function btreeGameWinningMove($root, $n, $x) {\n \n }\n}",
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"lang": "TypeScript",
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"langSlug": "typescript",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction btreeGameWinningMove(root: TreeNode | null, n: number, x: number): boolean {\n\n};",
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"lang": "Racket",
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"langSlug": "racket",
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"code": "; Definition for a binary tree node.\n#|\n\n; val : integer?\n; left : (or/c tree-node? #f)\n; right : (or/c tree-node? #f)\n(struct tree-node\n (val left right) #:mutable #:transparent)\n\n; constructor\n(define (make-tree-node [val 0])\n (tree-node val #f #f))\n\n|#\n\n(define/contract (btree-game-winning-move root n x)\n (-> (or/c tree-node? #f) exact-integer? exact-integer? boolean?)\n\n )",
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"code": "%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%% left = null :: 'null' | #tree_node{},\n%% right = null :: 'null' | #tree_node{}}).\n\n-spec btree_game_winning_move(Root :: #tree_node{} | null, N :: integer(), X :: integer()) -> boolean().\nbtree_game_winning_move(Root, N, X) ->\n .",
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"langSlug": "elixir",
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"code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec btree_game_winning_move(root :: TreeNode.t | nil, n :: integer, x :: integer) :: boolean\n def btree_game_winning_move(root, n, x) do\n\n end\nend",
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"hints": [
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"The best move y must be immediately adjacent to x, since it locks out that subtree.",
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"Can you count each of (up to) 3 different subtrees neighboring x?"
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],
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Java 8 features such as lambda expressions and stream API can be used. </p>\\r\\n\\r\\n<p>Most standard library headers are already included automatically for your convenience.</p>\\r\\n<p>Includes <code>Pair</code> class from https://docs.oracle.com/javase/8/javafx/api/javafx/util/Pair.html.</p>\"], \"python\": [\"Python\", \"<p><code>Python 2.7.12</code>.</p>\\r\\n\\r\\n<p>Most libraries are already imported automatically for your convenience, such as <a href=\\\"https://docs.python.org/2/library/array.html\\\" target=\\\"_blank\\\">array</a>, <a href=\\\"https://docs.python.org/2/library/bisect.html\\\" target=\\\"_blank\\\">bisect</a>, <a href=\\\"https://docs.python.org/2/library/collections.html\\\" target=\\\"_blank\\\">collections</a>. If you need more libraries, you can import it yourself.</p>\\r\\n\\r\\n<p>For Map/TreeMap data structure, you may use <a href=\\\"http://www.grantjenks.com/docs/sortedcontainers/\\\" target=\\\"_blank\\\">sortedcontainers</a> library.</p>\\r\\n\\r\\n<p>Note that Python 2.7 <a href=\\\"https://www.python.org/dev/peps/pep-0373/\\\" target=\\\"_blank\\\">will not be maintained past 2020</a>. 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