mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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50 lines
9.5 KiB
JSON
50 lines
9.5 KiB
JSON
{
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"data": {
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"question": {
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"questionId": "2865",
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"questionFrontendId": "2714",
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"boundTopicId": null,
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"title": "Find Shortest Path with K Hops",
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"titleSlug": "find-shortest-path-with-k-hops",
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"difficulty": "Hard",
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"likes": 6,
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"exampleTestcases": "4\n[[0,1,4],[0,2,2],[2,3,6]]\n1\n3\n2\n7\n[[3,1,9],[3,2,4],[4,0,9],[0,5,6],[3,6,2],[6,0,4],[1,2,4]]\n4\n1\n2\n5\n[[0,4,2],[0,1,3],[0,2,1],[2,1,4],[1,3,4],[3,4,7]]\n2\n3\n1",
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"categoryTitle": "Algorithms",
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"hints": [
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"Let's construct a new graph and run Dijkstra on it to get the answer to the problem.",
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"We define the new graph as follows: Each node of this graph is a pair (v, c) where v is a node from the given graph and c is any number between 0 and k (inclusive).",
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"Try to make edges of the defined graph in such a way that if we run Dijkstra on the node (s, 0), then the shortest path to node (d, k) would be the final answer.",
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"Edge type one: If the edge (v, u, w) belongs to the initial graph, we put an edge with the weight of w between nodes (v, c) and (u, c) for any c between 0 and k (inclusive) in the new graph.",
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"Edge type two: If the edge (v, u, w) belongs to the initial graph, we put an edge with the weight of 0 between nodes (v, c) and (u, c + 1), also between (u, c) and (v, c + 1) for any c between 0 and k - 1 (inclusive) in the new graph.",
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"For the matter of time complexity, note that you **don’t need** to literally construct the described graph."
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],
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"solution": null,
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"status": null,
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"sampleTestCase": "4\n[[0,1,4],[0,2,2],[2,3,6]]\n1\n3\n2",
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"metaData": "{\n \"name\": \"shortestPathWithHops\",\n \"params\": [\n {\n \"name\": \"n\",\n \"type\": \"integer\"\n },\n {\n \"type\": \"integer[][]\",\n \"name\": \"edges\"\n },\n {\n \"type\": \"integer\",\n \"name\": \"s\"\n },\n {\n \"type\": \"integer\",\n \"name\": \"d\"\n },\n {\n \"type\": \"integer\",\n \"name\": \"k\"\n }\n ],\n \"return\": {\n \"type\": \"integer\"\n }\n}",
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For the latest Python, please choose Python3 instead.</p>\"], \"c\": [\"C\", \"<p>Compiled with <code>gcc 8.2</code> using the gnu11 standard.</p>\\r\\n\\r\\n<p>Your code is compiled with level one optimization (<code>-O1</code>). <a href=\\\"https://github.com/google/sanitizers/wiki/AddressSanitizer\\\" target=\\\"_blank\\\">AddressSanitizer</a> is also enabled to help detect out-of-bounds and use-after-free bugs.</p>\\r\\n\\r\\n<p>Most standard library headers are already included automatically for your convenience.</p>\\r\\n\\r\\n<p>For hash table operations, you may use <a href=\\\"https://troydhanson.github.io/uthash/\\\" target=\\\"_blank\\\">uthash</a>. \\\"uthash.h\\\" is included by default. Below are some examples:</p>\\r\\n\\r\\n<p><b>1. Adding an item to a hash.</b>\\r\\n<pre>\\r\\nstruct hash_entry {\\r\\n int id; /* we'll use this field as the key */\\r\\n char name[10];\\r\\n UT_hash_handle hh; /* makes this structure hashable */\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry *s) {\\r\\n HASH_ADD_INT(users, id, s);\\r\\n}\\r\\n</pre>\\r\\n</p>\\r\\n\\r\\n<p><b>2. Looking up an item in a hash:</b>\\r\\n<pre>\\r\\nstruct hash_entry *find_user(int user_id) {\\r\\n struct hash_entry *s;\\r\\n HASH_FIND_INT(users, &user_id, s);\\r\\n return s;\\r\\n}\\r\\n</pre>\\r\\n</p>\\r\\n\\r\\n<p><b>3. 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