leetcode-problemset/leetcode-cn/originData/sum-of-beauty-of-all-substrings.json

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        "question": {
            "questionId": "1890",
            "questionFrontendId": "1781",
            "categoryTitle": "Algorithms",
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            "title": "Sum of Beauty of All Substrings",
            "titleSlug": "sum-of-beauty-of-all-substrings",
            "content": "<p>The <strong>beauty</strong> of a string is the difference in frequencies between the most frequent and least frequent characters.</p>\n\n<ul>\n\t<li>For example, the beauty of <code>&quot;abaacc&quot;</code> is <code>3 - 1 = 2</code>.</li>\n</ul>\n\n<p>Given a string <code>s</code>, return <em>the sum of <strong>beauty</strong> of all of its substrings.</em></p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;aabcb&quot;\n<strong>Output:</strong> 5\n<strong>Explanation: </strong>The substrings with non-zero beauty are [&quot;aab&quot;,&quot;aabc&quot;,&quot;aabcb&quot;,&quot;abcb&quot;,&quot;bcb&quot;], each with beauty equal to 1.</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;aabcbaa&quot;\n<strong>Output:</strong> 17\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;=<sup> </sup>500</code></li>\n\t<li><code>s</code> consists of only lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "所有子字符串美丽值之和",
            "translatedContent": "<p>一个字符串的 <strong>美丽值</strong> 定义为：出现频率最高字符与出现频率最低字符的出现次数之差。</p>\n\n<ul>\n\t<li>比方说，<code>\"abaacc\"</code> 的美丽值为 <code>3 - 1 = 2</code> 。</li>\n</ul>\n\n<p>给你一个字符串 <code>s</code> ，请你返回它所有子字符串的 <strong>美丽值</strong> 之和。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>s = \"aabcb\"\n<b>输出：</b>5\n<strong>解释：</strong>美丽值不为零的字符串包括 [\"aab\",\"aabc\",\"aabcb\",\"abcb\",\"bcb\"] ，每一个字符串的美丽值都为 1 。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>s = \"aabcbaa\"\n<b>输出：</b>17\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <=<sup> </sup>500</code></li>\n\t<li><code>s</code> 只包含小写英文字母。</li>\n</ul>\n",
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            "hints": [
                "Maintain a prefix sum for the frequencies of characters.",
                "You can iterate over all substring then iterate over the alphabet and find which character appears most and which appears least using the prefix sum array"
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