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"questionId": "973",
"questionFrontendId": "936",
"categoryTitle": "Algorithms",
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"title": "Stamping The Sequence",
"titleSlug": "stamping-the-sequence",
"content": "<p>You are given two strings <code>stamp</code> and <code>target</code>. Initially, there is a string <code>s</code> of length <code>target.length</code> with all <code>s[i] == &#39;?&#39;</code>.</p>\n\n<p>In one turn, you can place <code>stamp</code> over <code>s</code> and replace every letter in the <code>s</code> with the corresponding letter from <code>stamp</code>.</p>\n\n<ul>\n\t<li>For example, if <code>stamp = &quot;abc&quot;</code> and <code>target = &quot;abcba&quot;</code>, then <code>s</code> is <code>&quot;?????&quot;</code> initially. In one turn you can:\n\n\t<ul>\n\t\t<li>place <code>stamp</code> at index <code>0</code> of <code>s</code> to obtain <code>&quot;abc??&quot;</code>,</li>\n\t\t<li>place <code>stamp</code> at index <code>1</code> of <code>s</code> to obtain <code>&quot;?abc?&quot;</code>, or</li>\n\t\t<li>place <code>stamp</code> at index <code>2</code> of <code>s</code> to obtain <code>&quot;??abc&quot;</code>.</li>\n\t</ul>\n\tNote that <code>stamp</code> must be fully contained in the boundaries of <code>s</code> in order to stamp (i.e., you cannot place <code>stamp</code> at index <code>3</code> of <code>s</code>).</li>\n</ul>\n\n<p>We want to convert <code>s</code> to <code>target</code> using <strong>at most</strong> <code>10 * target.length</code> turns.</p>\n\n<p>Return <em>an array of the index of the left-most letter being stamped at each turn</em>. If we cannot obtain <code>target</code> from <code>s</code> within <code>10 * target.length</code> turns, return an empty array.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> stamp = &quot;abc&quot;, target = &quot;ababc&quot;\n<strong>Output:</strong> [0,2]\n<strong>Explanation:</strong> Initially s = &quot;?????&quot;.\n- Place stamp at index 0 to get &quot;abc??&quot;.\n- Place stamp at index 2 to get &quot;ababc&quot;.\n[1,0,2] would also be accepted as an answer, as well as some other answers.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> stamp = &quot;abca&quot;, target = &quot;aabcaca&quot;\n<strong>Output:</strong> [3,0,1]\n<strong>Explanation:</strong> Initially s = &quot;???????&quot;.\n- Place stamp at index 3 to get &quot;???abca&quot;.\n- Place stamp at index 0 to get &quot;abcabca&quot;.\n- Place stamp at index 1 to get &quot;aabcaca&quot;.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= stamp.length &lt;= target.length &lt;= 1000</code></li>\n\t<li><code>stamp</code> and <code>target</code> consist of lowercase English letters.</li>\n</ul>\n",
"translatedTitle": "戳印序列",
"translatedContent": "<p>你想要用<strong>小写字母</strong>组成一个目标字符串&nbsp;<code>target</code>。&nbsp;</p>\n\n<p>开始的时候,序列由&nbsp;<code>target.length</code>&nbsp;个&nbsp;<code>&#39;?&#39;</code>&nbsp;记号组成。而你有一个小写字母印章&nbsp;<code>stamp</code>。</p>\n\n<p>在每个回合,你可以将印章放在序列上,并将序列中的每个字母替换为印章上的相应字母。你最多可以进行&nbsp;<code>10 * target.length</code>&nbsp; 个回合。</p>\n\n<p>举个例子,如果初始序列为 &quot;?????&quot;,而你的印章 <code>stamp</code>&nbsp;是&nbsp;<code>&quot;abc&quot;</code>,那么在第一回合,你可以得到&nbsp;&quot;abc??&quot;、&quot;?abc?&quot;、&quot;??abc&quot;。(请注意,印章必须完全包含在序列的边界内才能盖下去。)</p>\n\n<p>如果可以印出序列,那么返回一个数组,该数组由每个回合中被印下的最左边字母的索引组成。如果不能印出序列,就返回一个空数组。</p>\n\n<p>例如,如果序列是 &quot;ababc&quot;,印章是 <code>&quot;abc&quot;</code>,那么我们就可以返回与操作&nbsp;&quot;?????&quot; -&gt; &quot;abc??&quot; -&gt; &quot;ababc&quot; 相对应的答案 <code>[0, 2]</code></p>\n\n<p>另外,如果可以印出序列,那么需要保证可以在 <code>10 * target.length</code>&nbsp;个回合内完成。任何超过此数字的答案将不被接受。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre><strong>输入:</strong>stamp = &quot;abc&quot;, target = &quot;ababc&quot;\n<strong>输出:</strong>[0,2]\n[1,0,2] 以及其他一些可能的结果也将作为答案被接受)\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre><strong>输入:</strong>stamp = &quot;abca&quot;, target = &quot;aabcaca&quot;\n<strong>输出:</strong>[3,0,1]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ol>\n\t<li><code>1 &lt;= stamp.length &lt;= target.length &lt;= 1000</code></li>\n\t<li><code>stamp</code> 和&nbsp;<code>target</code>&nbsp;只包含小写字母。</li>\n</ol>\n",
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