leetcode-problemset/leetcode-cn/originData/shortest-common-supersequence.json

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            "title": "Shortest Common Supersequence ",
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            "content": "<p>Given two strings <code>str1</code> and <code>str2</code>, return <em>the shortest string that has both </em><code>str1</code><em> and </em><code>str2</code><em> as <strong>subsequences</strong></em>. If there are multiple valid strings, return <strong>any</strong> of them.</p>\n\n<p>A string <code>s</code> is a <strong>subsequence</strong> of string <code>t</code> if deleting some number of characters from <code>t</code> (possibly <code>0</code>) results in the string <code>s</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> str1 = &quot;abac&quot;, str2 = &quot;cab&quot;\n<strong>Output:</strong> &quot;cabac&quot;\n<strong>Explanation:</strong> \nstr1 = &quot;abac&quot; is a subsequence of &quot;cabac&quot; because we can delete the first &quot;c&quot;.\nstr2 = &quot;cab&quot; is a subsequence of &quot;cabac&quot; because we can delete the last &quot;ac&quot;.\nThe answer provided is the shortest such string that satisfies these properties.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> str1 = &quot;aaaaaaaa&quot;, str2 = &quot;aaaaaaaa&quot;\n<strong>Output:</strong> &quot;aaaaaaaa&quot;\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= str1.length, str2.length &lt;= 1000</code></li>\n\t<li><code>str1</code> and <code>str2</code> consist of lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "最短公共超序列",
            "translatedContent": "<p>给出两个字符串&nbsp;<code>str1</code> 和&nbsp;<code>str2</code>，返回同时以&nbsp;<code>str1</code>&nbsp;和&nbsp;<code>str2</code>&nbsp;作为子序列的最短字符串。如果答案不止一个，则可以返回满足条件的任意一个答案。</p>\n\n<p>（如果从字符串 T 中删除一些字符（也可能不删除，并且选出的这些字符可以位于 T 中的&nbsp;<strong>任意位置</strong>），可以得到字符串 S，那么&nbsp;S 就是&nbsp;T 的子序列）</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例：</strong></p>\n\n<pre><strong>输入：</strong>str1 = &quot;abac&quot;, str2 = &quot;cab&quot;\n<strong>输出：</strong>&quot;cabac&quot;\n<strong>解释：</strong>\nstr1 = &quot;abac&quot; 是 &quot;cabac&quot; 的一个子串，因为我们可以删去 &quot;cabac&quot; 的第一个 &quot;c&quot;得到 &quot;abac&quot;。 \nstr2 = &quot;cab&quot; 是 &quot;cabac&quot; 的一个子串，因为我们可以删去 &quot;cabac&quot; 末尾的 &quot;ac&quot; 得到 &quot;cab&quot;。\n最终我们给出的答案是满足上述属性的最短字符串。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ol>\n\t<li><code>1 &lt;= str1.length, str2.length &lt;= 1000</code></li>\n\t<li><code>str1</code> 和&nbsp;<code>str2</code>&nbsp;都由小写英文字母组成。</li>\n</ol>\n",
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                "We can find the length of the longest common subsequence between str1[i:] and str2[j:] (for all (i, j)) by using dynamic programming.  We can use this information to recover the longest common supersequence."
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