mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
165 lines
20 KiB
JSON
165 lines
20 KiB
JSON
{
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"questionId": "1283",
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"questionFrontendId": "1507",
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"categoryTitle": "Algorithms",
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"boundTopicId": 321831,
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"title": "Reformat Date",
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"titleSlug": "reformat-date",
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"content": "<p>Given a <code>date</code> string in the form <code>Day Month Year</code>, where:</p>\n\n<ul>\n\t<li><code>Day</code> is in the set <code>{"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}</code>.</li>\n\t<li><code>Month</code> is in the set <code>{"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}</code>.</li>\n\t<li><code>Year</code> is in the range <code>[1900, 2100]</code>.</li>\n</ul>\n\n<p>Convert the date string to the format <code>YYYY-MM-DD</code>, where:</p>\n\n<ul>\n\t<li><code>YYYY</code> denotes the 4 digit year.</li>\n\t<li><code>MM</code> denotes the 2 digit month.</li>\n\t<li><code>DD</code> denotes the 2 digit day.</li>\n</ul>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> date = "20th Oct 2052"\n<strong>Output:</strong> "2052-10-20"\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> date = "6th Jun 1933"\n<strong>Output:</strong> "1933-06-06"\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> date = "26th May 1960"\n<strong>Output:</strong> "1960-05-26"\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The given dates are guaranteed to be valid, so no error handling is necessary.</li>\n</ul>\n",
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"translatedTitle": "转变日期格式",
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"translatedContent": "<p>给你一个字符串 <code>date</code> ，它的格式为 <code>Day Month Year</code> ，其中：</p>\n\n<ul>\n\t<li><code>Day</code> 是集合 <code>{"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}</code> 中的一个元素。</li>\n\t<li><code>Month</code> 是集合 <code>{"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}</code> 中的一个元素。</li>\n\t<li><code>Year</code> 的范围在 <code>[1900, 2100]</code> 之间。</li>\n</ul>\n\n<p>请你将字符串转变为 <code>YYYY-MM-DD</code> 的格式，其中：</p>\n\n<ul>\n\t<li><code>YYYY</code> 表示 4 位的年份。</li>\n\t<li><code>MM</code> 表示 2 位的月份。</li>\n\t<li><code>DD</code> 表示 2 位的天数。</li>\n</ul>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>date = "20th Oct 2052"\n<strong>输出：</strong>"2052-10-20"\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>date = "6th Jun 1933"\n<strong>输出：</strong>"1933-06-06"\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>date = "26th May 1960"\n<strong>输出：</strong>"1960-05-26"\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>给定日期保证是合法的，所以不需要处理异常输入。</li>\n</ul>\n",
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"difficulty": "Easy",
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"code": "# @param {String} date\n# @return {String}\ndef reformat_date(date)\n\nend",
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"code": "-spec reformat_date(Date :: unicode:unicode_binary()) -> unicode:unicode_binary().\nreformat_date(Date) ->\n .",
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"hints": [
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"Handle the conversions of day, month and year separately.",
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"Notice that days always have a two-word ending, so if you erase the last two characters of this days you'll get the number."
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"sampleTestCase": "\"20th Oct 2052\"",
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