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leetcode-problemset/leetcode-cn/originData/path-crossing.json
2022-05-02 23:44:12 +08:00

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{
"data": {
"question": {
"questionId": "1619",
"questionFrontendId": "1496",
"categoryTitle": "Algorithms",
"boundTopicId": 303610,
"title": "Path Crossing",
"titleSlug": "path-crossing",
"content": "<p>Given a string <code>path</code>, where <code>path[i] = &#39;N&#39;</code>, <code>&#39;S&#39;</code>, <code>&#39;E&#39;</code> or <code>&#39;W&#39;</code>, each representing moving one unit north, south, east, or west, respectively. You start at the origin <code>(0, 0)</code> on a 2D plane and walk on the path specified by <code>path</code>.</p>\n\n<p>Return <code>true</code> <em>if the path crosses itself at any point, that is, if at any time you are on a location you have previously visited</em>. Return <code>false</code> otherwise.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/06/10/screen-shot-2020-06-10-at-123929-pm.png\" style=\"width: 400px; height: 358px;\" />\n<pre>\n<strong>Input:</strong> path = &quot;NES&quot;\n<strong>Output:</strong> false \n<strong>Explanation:</strong> Notice that the path doesn&#39;t cross any point more than once.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/06/10/screen-shot-2020-06-10-at-123843-pm.png\" style=\"width: 400px; height: 339px;\" />\n<pre>\n<strong>Input:</strong> path = &quot;NESWW&quot;\n<strong>Output:</strong> true\n<strong>Explanation:</strong> Notice that the path visits the origin twice.</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= path.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>path[i]</code> is either <code>&#39;N&#39;</code>, <code>&#39;S&#39;</code>, <code>&#39;E&#39;</code>, or <code>&#39;W&#39;</code>.</li>\n</ul>\n",
"translatedTitle": "判断路径是否相交",
"translatedContent": "<p>给你一个字符串 <code>path</code>,其中 <code>path[i]</code> 的值可以是 <code>'N'</code>、<code>'S'</code>、<code>'E'</code> 或者 <code>'W'</code>,分别表示向北、向南、向东、向西移动一个单位。</p>\n\n<p>你从二维平面上的原点 <code>(0, 0)</code> 处开始出发,按 <code>path</code> 所指示的路径行走。</p>\n\n<p>如果路径在任何位置上与自身相交,也就是走到之前已经走过的位置,请返回 <code>true</code> ;否则,返回 <code>false</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/06/28/screen-shot-2020-06-10-at-123929-pm.png\" style=\"height: 358px; width: 400px;\" /></p>\n\n<pre>\n<strong>输入:</strong>path = \"NES\"\n<strong>输出:</strong>false \n<strong>解释:</strong>该路径没有在任何位置相交。</pre>\n\n<p><strong>示例 2</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/06/28/screen-shot-2020-06-10-at-123843-pm.png\" style=\"height: 339px; width: 400px;\" /></p>\n\n<pre>\n<strong>输入:</strong>path = \"NESWW\"\n<strong>输出:</strong>true\n<strong>解释:</strong>该路径经过原点两次。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= path.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>path[i]</code> 为 <code>'N'</code>、<code>'S'</code>、<code>'E'</code> 或 <code>'W'</code></li>\n</ul>\n",
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"topicTags": [
{
"name": "Hash Table",
"slug": "hash-table",
"translatedName": "哈希表",
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"code": "class Solution {\npublic:\n bool isPathCrossing(string path) {\n\n }\n};",
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"lang": "Python",
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"code": "class Solution(object):\n def isPathCrossing(self, path):\n \"\"\"\n :type path: str\n :rtype: bool\n \"\"\"",
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"code": "class Solution:\n def isPathCrossing(self, path: str) -> bool:",
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"code": "\n\nbool isPathCrossing(char * path){\n\n}",
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"code": "defmodule Solution do\n @spec is_path_crossing(path :: String.t) :: boolean\n def is_path_crossing(path) do\n\n end\nend",
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"hints": [
"Simulate the process while keeping track of visited points.",
"Use a set to store previously visited points."
],
"solution": null,
"status": null,
"sampleTestCase": "\"NES\"",
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