mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
190 lines
19 KiB
JSON
190 lines
19 KiB
JSON
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"questionId": "100184",
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"questionFrontendId": "面试题 01.04",
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"categoryTitle": "LCCI",
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"boundTopicId": 47062,
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"title": "Palindrome Permutation LCCI",
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"titleSlug": "palindrome-permutation-lcci",
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"content": "<p>Given a string, write a function to check if it is a permutation of a palindrome. A palindrome is a word or phrase that is the same forwards and backwards. A permutation is a rearrangement of letters. The palindrome does not need to be limited to just dictionary words.</p>\r\n\r\n<p> </p>\r\n\r\n<p><strong>Example1: </strong></p>\r\n\r\n<pre>\r\n<strong>Input: "</strong>tactcoa"\r\n<strong>Output: </strong>true（permutations: "tacocat"、"atcocta", etc.）\r\n</pre>\r\n\r\n<p> </p>\r\n",
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"translatedTitle": "回文排列",
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"translatedContent": "<p>给定一个字符串，编写一个函数判定其是否为某个回文串的排列之一。</p>\n\n<p>回文串是指正反两个方向都一样的单词或短语。排列是指字母的重新排列。</p>\n\n<p>回文串不一定是字典当中的单词。</p>\n\n<p> </p>\n\n<p><strong>示例1：</strong></p>\n\n<pre><strong>输入："</strong>tactcoa"\n<strong>输出：</strong>true（排列有"tacocat"、"atcocta"，等等）\n</pre>\n\n<p> </p>\n",
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"difficulty": "Easy",
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"name": "Bit Manipulation",
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"code": "class Solution {\npublic:\n bool canPermutePalindrome(string s) {\n\n }\n};",
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"code": "class Solution(object):\n def canPermutePalindrome(self, s):\n \"\"\"\n :type s: str\n :rtype: bool\n \"\"\"",
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"lang": "Erlang",
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"langSlug": "erlang",
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"code": "-spec can_permute_palindrome(S :: unicode:unicode_binary()) -> boolean().\ncan_permute_palindrome(S) ->\n .",
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"__typename": "CodeSnippetNode"
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},
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"lang": "Elixir",
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"langSlug": "elixir",
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"code": "defmodule Solution do\n @spec can_permute_palindrome(s :: String.t) :: boolean\n def can_permute_palindrome(s) do\n\n end\nend",
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"hints": [
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"你不必且也不应该生成所有的排列。这将极为低效。",
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"作为回文排列的字符串有什么特征？",
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"你试过散列表吗？你应该能把它降到O(N)的时间。",
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"使用位向量可以减少空间使用吗？"
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],
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