leetcode-problemset/leetcode-cn/originData/pairs-of-songs-with-total-durations-divisible-by-60.json

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            "title": "Pairs of Songs With Total Durations Divisible by 60",
            "titleSlug": "pairs-of-songs-with-total-durations-divisible-by-60",
            "content": "<p>You are given a list of songs where the <code>i<sup>th</sup></code> song has a duration of <code>time[i]</code> seconds.</p>\n\n<p>Return <em>the number of pairs of songs for which their total duration in seconds is divisible by</em> <code>60</code>. Formally, we want the number of indices <code>i</code>, <code>j</code> such that <code>i &lt; j</code> with <code>(time[i] + time[j]) % 60 == 0</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> time = [30,20,150,100,40]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> Three pairs have a total duration divisible by 60:\n(time[0] = 30, time[2] = 150): total duration 180\n(time[1] = 20, time[3] = 100): total duration 120\n(time[1] = 20, time[4] = 40): total duration 60\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> time = [60,60,60]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> All three pairs have a total duration of 120, which is divisible by 60.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= time.length &lt;= 6 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= time[i] &lt;= 500</code></li>\n</ul>\n",
            "translatedTitle": "总持续时间可被 60 整除的歌曲",
            "translatedContent": "<p>在歌曲列表中，第 <code>i</code> 首歌曲的持续时间为 <code>time[i]</code> 秒。</p>\n\n<p>返回其总持续时间（以秒为单位）可被 <code>60</code> 整除的歌曲对的数量。形式上，我们希望下标数字 <code>i</code> 和 <code>j</code> 满足&nbsp; <code>i &lt; j</code> 且有&nbsp;<code>(time[i] + time[j]) % 60 == 0</code>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>time = [30,20,150,100,40]\n<strong>输出：</strong>3\n<strong>解释：</strong>这三对的总持续时间可被 60 整除：\n(time[0] = 30, time[2] = 150): 总持续时间 180\n(time[1] = 20, time[3] = 100): 总持续时间 120\n(time[1] = 20, time[4] = 40): 总持续时间 60\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>time = [60,60,60]\n<strong>输出：</strong>3\n<strong>解释：</strong>所有三对的总持续时间都是 120，可以被 60 整除。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= time.length &lt;= 6 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= time[i] &lt;= 500</code></li>\n</ul>\n",
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