leetcode-problemset/leetcode-cn/originData/optimal-partition-of-string.json

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        "question": {
            "questionId": "2487",
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            "categoryTitle": "Algorithms",
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            "title": "Optimal Partition of String",
            "titleSlug": "optimal-partition-of-string",
            "content": "<p>Given a string <code>s</code>, partition the string into one or more <strong>substrings</strong> such that the characters in each substring are <strong>unique</strong>. That is, no letter appears in a single substring more than <strong>once</strong>.</p>\n\n<p>Return <em>the <strong>minimum</strong> number of substrings in such a partition.</em></p>\n\n<p>Note that each character should belong to exactly one substring in a partition.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;abacaba&quot;\n<strong>Output:</strong> 4\n<strong>Explanation:</strong>\nTwo possible partitions are (&quot;a&quot;,&quot;ba&quot;,&quot;cab&quot;,&quot;a&quot;) and (&quot;ab&quot;,&quot;a&quot;,&quot;ca&quot;,&quot;ba&quot;).\nIt can be shown that 4 is the minimum number of substrings needed.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;ssssss&quot;\n<strong>Output:</strong> 6\n<strong>Explanation:\n</strong>The only valid partition is (&quot;s&quot;,&quot;s&quot;,&quot;s&quot;,&quot;s&quot;,&quot;s&quot;,&quot;s&quot;).\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> consists of only English lowercase letters.</li>\n</ul>\n",
            "translatedTitle": "子字符串的最优划分",
            "translatedContent": "<p>给你一个字符串 <code>s</code> ，请你将该字符串划分成一个或多个 <strong>子字符串</strong> ，并满足每个子字符串中的字符都是 <strong>唯一</strong> 的。也就是说，在单个子字符串中，字母的出现次数都不超过 <strong>一次</strong> 。</p>\n\n<p>满足题目要求的情况下，返回 <strong>最少</strong> 需要划分多少个子字符串<em>。</em></p>\n\n<p>注意，划分后，原字符串中的每个字符都应该恰好属于一个子字符串。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"abacaba\"\n<strong>输出：</strong>4\n<strong>解释：</strong>\n两种可行的划分方法分别是 (\"a\",\"ba\",\"cab\",\"a\") 和 (\"ab\",\"a\",\"ca\",\"ba\") 。\n可以证明最少需要划分 4 个子字符串。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"ssssss\"\n<strong>输出：</strong>6\n<strong>解释：\n</strong>只存在一种可行的划分方法 (\"s\",\"s\",\"s\",\"s\",\"s\",\"s\") 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> 仅由小写英文字母组成</li>\n</ul>\n",
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            "hints": [
                "Try to come up with a greedy approach.",
                "From left to right, extend every substring in the partition as much as possible."
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