mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
178 lines
20 KiB
JSON
178 lines
20 KiB
JSON
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"questionId": "1770",
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"questionFrontendId": "1647",
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"categoryTitle": "Algorithms",
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"boundTopicId": 473570,
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"title": "Minimum Deletions to Make Character Frequencies Unique",
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"content": "<p>A string <code>s</code> is called <strong>good</strong> if there are no two different characters in <code>s</code> that have the same <strong>frequency</strong>.</p>\n\n<p>Given a string <code>s</code>, return<em> the <strong>minimum</strong> number of characters you need to delete to make </em><code>s</code><em> <strong>good</strong>.</em></p>\n\n<p>The <strong>frequency</strong> of a character in a string is the number of times it appears in the string. For example, in the string <code>"aab"</code>, the <strong>frequency</strong> of <code>'a'</code> is <code>2</code>, while the <strong>frequency</strong> of <code>'b'</code> is <code>1</code>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "aab"\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> <code>s</code> is already good.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "aaabbbcc"\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> You can delete two 'b's resulting in the good string "aaabcc".\nAnother way it to delete one 'b' and one 'c' resulting in the good string "aaabbc".</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "ceabaacb"\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> You can delete both 'c's resulting in the good string "eabaab".\nNote that we only care about characters that are still in the string at the end (i.e. frequency of 0 is ignored).\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 10<sup>5</sup></code></li>\n\t<li><code>s</code> contains only lowercase English letters.</li>\n</ul>\n",
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"translatedTitle": "字符频次唯一的最小删除次数",
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"translatedContent": "<p>如果字符串 <code>s</code> 中 <strong>不存在</strong> 两个不同字符 <strong>频次</strong> 相同的情况，就称 <code>s</code> 是 <strong>优质字符串</strong> 。</p>\n\n<p>给你一个字符串 <code>s</code>，返回使 <code>s</code> 成为 <strong>优质字符串</strong> 需要删除的 <strong>最小</strong> 字符数。</p>\n\n<p>字符串中字符的 <strong>频次</strong> 是该字符在字符串中的出现次数。例如，在字符串 <code>\"aab\"</code> 中，<code>'a'</code> 的频次是 <code>2</code>，而 <code>'b'</code> 的频次是 <code>1</code> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"aab\"\n<strong>输出：</strong>0\n<strong>解释：</strong><code>s</code> 已经是优质字符串。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"aaabbbcc\"\n<strong>输出：</strong>2\n<strong>解释：</strong>可以删除两个 'b' , 得到优质字符串 \"aaabcc\" 。\n另一种方式是删除一个 'b' 和一个 'c' ，得到优质字符串 \"aaabbc\" 。</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"ceabaacb\"\n<strong>输出：</strong>2\n<strong>解释：</strong>可以删除两个 'c' 得到优质字符串 \"eabaab\" 。\n注意，只需要关注结果字符串中仍然存在的字符。（即，频次为 0 的字符会忽略不计。）\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 10<sup>5</sup></code></li>\n\t<li><code>s</code> 仅含小写英文字母</li>\n</ul>\n",
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"As we can only delete characters, if we have multiple characters having the same frequency, we must decrease all the frequencies of them, except one.",
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"Sort the alphabet characters by their frequencies non-increasingly.",
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"Iterate on the alphabet characters, keep decreasing the frequency of the current character until it reaches a value that has not appeared before."
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