mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
180 lines
19 KiB
JSON
180 lines
19 KiB
JSON
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"title": "Maximum XOR of Two Numbers in an Array",
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"content": "<p>Given an integer array <code>nums</code>, return <em>the maximum result of </em><code>nums[i] XOR nums[j]</code>, where <code>0 <= i <= j < n</code>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,10,5,25,2,8]\n<strong>Output:</strong> 28\n<strong>Explanation:</strong> The maximum result is 5 XOR 25 = 28.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [14,70,53,83,49,91,36,80,92,51,66,70]\n<strong>Output:</strong> 127\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 2 * 10<sup>5</sup></code></li>\n\t<li><code>0 <= nums[i] <= 2<sup>31</sup> - 1</code></li>\n</ul>\n",
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"translatedTitle": "数组中两个数的最大异或值",
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"translatedContent": "<p>给你一个整数数组 <code>nums</code> ，返回<em> </em><code>nums[i] XOR nums[j]</code> 的最大运算结果，其中 <code>0 ≤ i ≤ j < n</code> 。</p>\n\n<p><strong>进阶：</strong>你可以在 <code>O(n)</code> 的时间解决这个问题吗？</p>\n\n<p> </p>\n\n<div class=\"original__bRMd\">\n<div>\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [3,10,5,25,2,8]\n<strong>输出：</strong>28\n<strong>解释：</strong>最大运算结果是 5 XOR 25 = 28.</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [0]\n<strong>输出：</strong>0\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [2,4]\n<strong>输出：</strong>6\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [8,10,2]\n<strong>输出：</strong>10\n</pre>\n\n<p><strong>示例 5：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [14,70,53,83,49,91,36,80,92,51,66,70]\n<strong>输出：</strong>127\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 2 * 10<sup>4</sup></code></li>\n\t<li><code>0 <= nums[i] <= 2<sup>31</sup> - 1</code></li>\n</ul>\n</div>\n</div>\n",
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