leetcode-problemset/leetcode-cn/originData/longest-subarray-with-maximum-bitwise-and.json

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            "title": "Longest Subarray With Maximum Bitwise AND",
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            "content": "<p>You are given an integer array <code>nums</code> of size <code>n</code>.</p>\n\n<p>Consider a <strong>non-empty</strong> subarray from <code>nums</code> that has the <strong>maximum</strong> possible <strong>bitwise AND</strong>.</p>\n\n<ul>\n\t<li>In other words, let <code>k</code> be the maximum value of the bitwise AND of <strong>any</strong> subarray of <code>nums</code>. Then, only subarrays with a bitwise AND equal to <code>k</code> should be considered.</li>\n</ul>\n\n<p>Return <em>the length of the <strong>longest</strong> such subarray</em>.</p>\n\n<p>The bitwise AND of an array is the bitwise AND of all the numbers in it.</p>\n\n<p>A <strong>subarray</strong> is a contiguous sequence of elements within an array.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,3,2,2]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong>\nThe maximum possible bitwise AND of a subarray is 3.\nThe longest subarray with that value is [3,3], so we return 2.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4]\n<strong>Output:</strong> 1\n<strong>Explanation:</strong>\nThe maximum possible bitwise AND of a subarray is 4.\nThe longest subarray with that value is [4], so we return 1.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>6</sup></code></li>\n</ul>\n",
            "translatedTitle": "按位与最大的最长子数组",
            "translatedContent": "<p>给你一个长度为 <code>n</code> 的整数数组 <code>nums</code> 。</p>\n\n<p>考虑 <code>nums</code> 中进行 <strong>按位与（bitwise AND）</strong>运算得到的值 <strong>最大</strong> 的 <strong>非空</strong> 子数组。</p>\n\n<ul>\n\t<li>换句话说，令 <code>k</code> 是 <code>nums</code> <strong>任意</strong> 子数组执行按位与运算所能得到的最大值。那么，只需要考虑那些执行一次按位与运算后等于 <code>k</code> 的子数组。</li>\n</ul>\n\n<p>返回满足要求的 <strong>最长</strong> 子数组的长度。</p>\n\n<p>数组的按位与就是对数组中的所有数字进行按位与运算。</p>\n\n<p><strong>子数组</strong> 是数组中的一个连续元素序列。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,3,3,2,2]\n<strong>输出：</strong>2\n<strong>解释：</strong>\n子数组按位与运算的最大值是 3 。\n能得到此结果的最长子数组是 [3,3]，所以返回 2 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,3,4]\n<strong>输出：</strong>1\n<strong>解释：</strong>\n子数组按位与运算的最大值是 4 。 \n能得到此结果的最长子数组是 [4]，所以返回 1 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>6</sup></code></li>\n</ul>\n",
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                "Notice that the bitwise AND of two different numbers will always be strictly less than the maximum of those two numbers.",
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