leetcode-problemset/leetcode-cn/originData/linked-list-components.json

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        "question": {
            "questionId": "835",
            "questionFrontendId": "817",
            "categoryTitle": "Algorithms",
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            "title": "Linked List Components",
            "titleSlug": "linked-list-components",
            "content": "<p>You are given the <code>head</code> of a linked list containing unique integer values and an integer array <code>nums</code> that is a subset of the linked list values.</p>\n\n<p>Return <em>the number of connected components in </em><code>nums</code><em> where two values are connected if they appear <strong>consecutively</strong> in the linked list</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/07/22/lc-linkedlistcom1.jpg\" style=\"width: 424px; height: 65px;\" />\n<pre>\n<strong>Input:</strong> head = [0,1,2,3], nums = [0,1,3]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> 0 and 1 are connected, so [0, 1] and [3] are the two connected components.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/07/22/lc-linkedlistcom2.jpg\" style=\"width: 544px; height: 65px;\" />\n<pre>\n<strong>Input:</strong> head = [0,1,2,3,4], nums = [0,3,1,4]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> 0 and 1 are connected, 3 and 4 are connected, so [0, 1] and [3, 4] are the two connected components.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the linked list is <code>n</code>.</li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= Node.val &lt; n</code></li>\n\t<li>All the values <code>Node.val</code> are <strong>unique</strong>.</li>\n\t<li><code>1 &lt;= nums.length &lt;= n</code></li>\n\t<li><code>0 &lt;= nums[i] &lt; n</code></li>\n\t<li>All the values of <code>nums</code> are <strong>unique</strong>.</li>\n</ul>\n",
            "translatedTitle": "链表组件",
            "translatedContent": "<p>给定链表头结点&nbsp;<code>head</code>，该链表上的每个结点都有一个 <strong>唯一的整型值</strong> 。同时给定列表&nbsp;<code>nums</code>，该列表是上述链表中整型值的一个子集。</p>\n\n<p>返回列表&nbsp;<code>nums</code>&nbsp;中组件的个数，这里对组件的定义为：链表中一段最长连续结点的值（该值必须在列表&nbsp;<code>nums</code>&nbsp;中）构成的集合。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例&nbsp;1：</strong></p>\n\n<p><img src=\"https://assets.leetcode.com/uploads/2021/07/22/lc-linkedlistcom1.jpg\" /></p>\n\n<pre>\n<strong>输入:</strong> head = [0,1,2,3], nums = [0,1,3]\n<strong>输出:</strong> 2\n<strong>解释:</strong> 链表中,0 和 1 是相连接的，且 nums 中不包含 2，所以 [0, 1] 是 nums 的一个组件，同理 [3] 也是一个组件，故返回 2。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<p><strong>&nbsp;</strong><img src=\"https://assets.leetcode.com/uploads/2021/07/22/lc-linkedlistcom2.jpg\" /></p>\n\n<pre>\n<strong>输入:</strong> head = [0,1,2,3,4], nums = [0,3,1,4]\n<strong>输出:</strong> 2\n<strong>解释:</strong> 链表中，0 和 1 是相连接的，3 和 4 是相连接的，所以 [0, 1] 和 [3, 4] 是两个组件，故返回 2。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>链表中节点数为<code>n</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= Node.val &lt; n</code></li>\n\t<li><code>Node.val</code>&nbsp;中所有值 <strong>不同</strong></li>\n\t<li><code>1 &lt;= nums.length &lt;= n</code></li>\n\t<li><code>0 &lt;= nums[i] &lt; n</code></li>\n\t<li><code>nums</code> 中所有值 <strong>不同</strong></li>\n</ul>\n",
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                    "code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n *     int val;\n *     ListNode *next;\n *     ListNode() : val(0), next(nullptr) {}\n *     ListNode(int x) : val(x), next(nullptr) {}\n *     ListNode(int x, ListNode *next) : val(x), next(next) {}\n * };\n */\nclass Solution {\npublic:\n    int numComponents(ListNode* head, vector<int>& nums) {\n\n    }\n};",
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                    "code": "; Definition for singly-linked list:\n#|\n\n; val : integer?\n; next : (or/c list-node? #f)\n(struct list-node\n  (val next) #:mutable #:transparent)\n\n; constructor\n(define (make-list-node [val 0])\n  (list-node val #f))\n\n|#\n\n(define/contract (num-components head nums)\n  (-> (or/c list-node? #f) (listof exact-integer?) exact-integer?)\n\n  )",
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1.17<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 <a href=\\\"https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods\\\" target=\\\"_blank\\\">https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.10<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 \\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u9700\\u4f7f\\u7528 Map\\/TreeMap \\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"http:\\/\\/www.grantjenks.com\\/docs\\/sortedcontainers\\/\\\" target=\\\"_blank\\\">sortedcontainers<\\/a> \\u5e93\\u3002<\\/p>\"],\"scala\":[\"Scala\",\"<p>\\u7248\\u672c\\uff1a<code>Scala 2.13<\\/code><\\/p>\"],\"kotlin\":[\"Kotlin\",\"<p>\\u7248\\u672c\\uff1a<code>Kotlin 1.3.10<\\/code><\\/p>\"],\"rust\":[\"Rust\",\"<p>\\u7248\\u672c\\uff1a<code>rust 1.58.1<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 crates.io \\u7684 <a href=\\\"https:\\/\\/crates.io\\/crates\\/rand\\\" target=\\\"_blank\\\">rand<\\/a><\\/p>\"],\"php\":[\"PHP\",\"<p><code>PHP 8.1<\\/code>.<\\/p>\\r\\n\\r\\n<p>With bcmath module.<\\/p>\"],\"typescript\":[\"TypeScript\",\"<p>TypeScript 4.5.4<\\/p>\\r\\n\\r\\n<p>Compile Options: --alwaysStrict --strictBindCallApply --strictFunctionTypes --target ES2020<\\/p>\"],\"racket\":[\"Racket\",\"<p><a href=\\\"https:\\/\\/docs.racket-lang.org\\/guide\\/performance.html#%28tech._c%29\\\" target=\\\"_blank\\\">Racket CS<\\/a> v8.3<\\/p>\\r\\n\\r\\n<p>\\u4f7f\\u7528 #lang racket<\\/p>\\r\\n\\r\\n<p>\\u5df2\\u9884\\u5148 (require data\\/gvector data\\/queue data\\/order data\\/heap). \\u82e5\\u9700\\u4f7f\\u7528\\u5176\\u5b83\\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u53ef\\u81ea\\u884c require\\u3002<\\/p>\"],\"erlang\":[\"Erlang\",\"Erlang\\/OTP 24.2\"],\"elixir\":[\"Elixir\",\"Elixir 1.13.0 with Erlang\\/OTP 24.2\"]}",
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