mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
185 lines
19 KiB
JSON
185 lines
19 KiB
JSON
{
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"questionId": "100281",
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"questionFrontendId": "剑指 Offer 13",
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"categoryTitle": "LCOF",
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"boundTopicId": 85457,
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"title": "机器人的运动范围 LCOF",
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"titleSlug": "ji-qi-ren-de-yun-dong-fan-wei-lcof",
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"content": "English description is not available for the problem. Please switch to Chinese.",
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"translatedTitle": "机器人的运动范围",
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"translatedContent": "<p>地上有一个m行n列的方格，从坐标 <code>[0,0]</code> 到坐标 <code>[m-1,n-1]</code> 。一个机器人从坐标 <code>[0, 0] </code>的格子开始移动，它每次可以向左、右、上、下移动一格（不能移动到方格外），也不能进入行坐标和列坐标的数位之和大于k的格子。例如，当k为18时，机器人能够进入方格 [35, 37] ，因为3+5+3+7=18。但它不能进入方格 [35, 38]，因为3+5+3+8=19。请问该机器人能够到达多少个格子？</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>m = 2, n = 3, k = 1\n<strong>输出：</strong>3\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>m = 3, n = 1, k = 0\n<strong>输出：</strong>1\n</pre>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= n,m <= 100</code></li>\n\t<li><code>0 <= k <= 20</code></li>\n</ul>\n",
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"difficulty": "Medium",
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"name": "Depth-First Search",
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"translatedName": "深度优先搜索",
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"name": "Breadth-First Search",
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"name": "Dynamic Programming",
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"code": "class Solution {\npublic:\n int movingCount(int m, int n, int k) {\n\n }\n};",
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"code": "class Solution {\n public int movingCount(int m, int n, int k) {\n\n }\n}",
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"code": "class Solution(object):\n def movingCount(self, m, n, k):\n \"\"\"\n :type m: int\n :type n: int\n :type k: int\n :rtype: int\n \"\"\"",
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"code": "# @param {Integer} m\n# @param {Integer} n\n# @param {Integer} k\n# @return {Integer}\ndef moving_count(m, n, k)\n\nend",
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