mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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168 lines
25 KiB
JSON
168 lines
25 KiB
JSON
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"questionId": "1043",
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"title": "Grid Illumination",
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"content": "<p>There is a 2D <code>grid</code> of size <code>n x n</code> where each cell of this grid has a lamp that is initially <strong>turned off</strong>.</p>\n\n<p>You are given a 2D array of lamp positions <code>lamps</code>, where <code>lamps[i] = [row<sub>i</sub>, col<sub>i</sub>]</code> indicates that the lamp at <code>grid[row<sub>i</sub>][col<sub>i</sub>]</code> is <strong>turned on</strong>. Even if the same lamp is listed more than once, it is turned on.</p>\n\n<p>When a lamp is turned on, it <strong>illuminates its cell</strong> and <strong>all other cells</strong> in the same <strong>row, column, or diagonal</strong>.</p>\n\n<p>You are also given another 2D array <code>queries</code>, where <code>queries[j] = [row<sub>j</sub>, col<sub>j</sub>]</code>. For the <code>j<sup>th</sup></code> query, determine whether <code>grid[row<sub>j</sub>][col<sub>j</sub>]</code> is illuminated or not. After answering the <code>j<sup>th</sup></code> query, <strong>turn off</strong> the lamp at <code>grid[row<sub>j</sub>][col<sub>j</sub>]</code> and its <strong>8 adjacent lamps</strong> if they exist. A lamp is adjacent if its cell shares either a side or corner with <code>grid[row<sub>j</sub>][col<sub>j</sub>]</code>.</p>\n\n<p>Return <em>an array of integers </em><code>ans</code><em>,</em><em> where </em><code>ans[j]</code><em> should be </em><code>1</code><em> if the cell in the </em><code>j<sup>th</sup></code><em> query was illuminated, or </em><code>0</code><em> if the lamp was not.</em></p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/08/19/illu_1.jpg\" style=\"width: 750px; height: 209px;\" />\n<pre>\n<strong>Input:</strong> n = 5, lamps = [[0,0],[4,4]], queries = [[1,1],[1,0]]\n<strong>Output:</strong> [1,0]\n<strong>Explanation:</strong> We have the initial grid with all lamps turned off. In the above picture we see the grid after turning on the lamp at grid[0][0] then turning on the lamp at grid[4][4].\nThe 0<sup>th</sup> query asks if the lamp at grid[1][1] is illuminated or not (the blue square). It is illuminated, so set ans[0] = 1. Then, we turn off all lamps in the red square.\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/08/19/illu_step1.jpg\" style=\"width: 500px; height: 218px;\" />\nThe 1<sup>st</sup> query asks if the lamp at grid[1][0] is illuminated or not (the blue square). It is not illuminated, so set ans[1] = 0. Then, we turn off all lamps in the red rectangle.\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/08/19/illu_step2.jpg\" style=\"width: 500px; height: 219px;\" />\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 5, lamps = [[0,0],[4,4]], queries = [[1,1],[1,1]]\n<strong>Output:</strong> [1,1]\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 5, lamps = [[0,0],[0,4]], queries = [[0,4],[0,1],[1,4]]\n<strong>Output:</strong> [1,1,0]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= n <= 10<sup>9</sup></code></li>\n\t<li><code>0 <= lamps.length <= 20000</code></li>\n\t<li><code>0 <= queries.length <= 20000</code></li>\n\t<li><code>lamps[i].length == 2</code></li>\n\t<li><code>0 <= row<sub>i</sub>, col<sub>i</sub> < n</code></li>\n\t<li><code>queries[j].length == 2</code></li>\n\t<li><code>0 <= row<sub>j</sub>, col<sub>j</sub> < n</code></li>\n</ul>\n",
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"translatedTitle": "网格照明",
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"translatedContent": "<p>在大小为 <code>n x n</code> 的网格 <code>grid</code> 上，每个单元格都有一盏灯，最初灯都处于 <strong>关闭</strong> 状态。</p>\n\n<p>给你一个由灯的位置组成的二维数组 <code>lamps</code> ，其中 <code>lamps[i] = [row<sub>i</sub>, col<sub>i</sub>]</code> 表示 <strong>打开</strong> 位于 <code>grid[row<sub>i</sub>][col<sub>i</sub>]</code> 的灯。即便同一盏灯可能在 <code>lamps</code> 中多次列出，不会影响这盏灯处于 <strong>打开</strong> 状态。</p>\n\n<p>当一盏灯处于打开状态，它将会照亮 <strong>自身所在单元格</strong> 以及同一 <strong>行</strong> 、同一 <strong>列</strong> 和两条 <strong>对角线</strong> 上的 <strong>所有其他单元格</strong> 。</p>\n\n<p>另给你一个二维数组 <code>queries</code> ，其中 <code>queries[j] = [row<sub>j</sub>, col<sub>j</sub>]</code> 。对于第 <code>j</code> 个查询，如果单元格 <code>[row<sub>j</sub>, col<sub>j</sub>]</code> 是被照亮的，则查询结果为 <code>1</code> ，否则为 <code>0</code> 。在第 <code>j</code> 次查询之后 [按照查询的顺序] ，<strong>关闭</strong> 位于单元格 <code>grid[row<sub>j</sub>][col<sub>j</sub>]</code> 上及相邻 8 个方向上（与单元格 <code>grid[row<sub>i</sub>][col<sub>i</sub>]</code> 共享角或边）的任何灯。</p>\n\n<p>返回一个整数数组 <code>ans</code> 作为答案， <code>ans[j]</code> 应等于第 <code>j</code> 次查询 <code>queries[j]</code> 的结果，<code>1</code> 表示照亮，<code>0</code> 表示未照亮。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/08/19/illu_1.jpg\" style=\"height: 209px; width: 750px;\" />\n<pre>\n<strong>输入：</strong>n = 5, lamps = [[0,0],[4,4]], queries = [[1,1],[1,0]]\n<strong>输出：</strong>[1,0]\n<strong>解释：</strong>最初所有灯都是关闭的。在执行查询之前，打开位于 [0, 0] 和 [4, 4] 的灯。第 0 次查询检查 grid[1][1] 是否被照亮（蓝色方框）。该单元格被照亮，所以 ans[0] = 1 。然后，关闭红色方框中的所有灯。\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/08/19/illu_step1.jpg\" style=\"height: 218px; width: 500px;\" />\n第 1 次查询检查 grid[1][0] 是否被照亮（蓝色方框）。该单元格没有被照亮，所以 ans[1] = 0 。然后，关闭红色矩形中的所有灯。\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/08/19/illu_step2.jpg\" style=\"height: 219px; width: 500px;\" />\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 5, lamps = [[0,0],[4,4]], queries = [[1,1],[1,1]]\n<strong>输出：</strong>[1,1]\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 5, lamps = [[0,0],[0,4]], queries = [[0,4],[0,1],[1,4]]\n<strong>输出：</strong>[1,1,0]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= n <= 10<sup>9</sup></code></li>\n\t<li><code>0 <= lamps.length <= 20000</code></li>\n\t<li><code>0 <= queries.length <= 20000</code></li>\n\t<li><code>lamps[i].length == 2</code></li>\n\t<li><code>0 <= row<sub>i</sub>, col<sub>i</sub> < n</code></li>\n\t<li><code>queries[j].length == 2</code></li>\n\t<li><code>0 <= row<sub>j</sub>, col<sub>j</sub> < n</code></li>\n</ul>\n",
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