leetcode-problemset/leetcode-cn/originData/greatest-common-divisor-of-strings.json

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        "question": {
            "questionId": "1146",
            "questionFrontendId": "1071",
            "categoryTitle": "Algorithms",
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            "title": "Greatest Common Divisor of Strings",
            "titleSlug": "greatest-common-divisor-of-strings",
            "content": "<p>For two strings <code>s</code> and <code>t</code>, we say &quot;<code>t</code> divides <code>s</code>&quot; if and only if <code>s = t + ... + t</code> (i.e., <code>t</code> is concatenated with itself one or more times).</p>\n\n<p>Given two strings <code>str1</code> and <code>str2</code>, return <em>the largest string </em><code>x</code><em> such that </em><code>x</code><em> divides both </em><code>str1</code><em> and </em><code>str2</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> str1 = &quot;ABCABC&quot;, str2 = &quot;ABC&quot;\n<strong>Output:</strong> &quot;ABC&quot;\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> str1 = &quot;ABABAB&quot;, str2 = &quot;ABAB&quot;\n<strong>Output:</strong> &quot;AB&quot;\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> str1 = &quot;LEET&quot;, str2 = &quot;CODE&quot;\n<strong>Output:</strong> &quot;&quot;\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= str1.length, str2.length &lt;= 1000</code></li>\n\t<li><code>str1</code> and <code>str2</code> consist of English uppercase letters.</li>\n</ul>\n",
            "translatedTitle": "字符串的最大公因子",
            "translatedContent": "<p>对于字符串&nbsp;<code>s</code> 和&nbsp;<code>t</code>，只有在&nbsp;<code>s = t + ... + t</code>（<code>t</code> 自身连接 1 次或多次）时，我们才认定&nbsp;“<code>t</code> 能除尽 <code>s</code>”。</p>\n\n<p>给定两个字符串&nbsp;<code>str1</code>&nbsp;和&nbsp;<code>str2</code>&nbsp;。返回 <em>最长字符串&nbsp;<code>x</code>，要求满足&nbsp;<code>x</code> 能除尽 <code>str1</code> 且&nbsp;<code>X</code> 能除尽 <code>str2</code></em> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>str1 = \"ABCABC\", str2 = \"ABC\"\n<strong>输出：</strong>\"ABC\"\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>str1 = \"ABABAB\", str2 = \"ABAB\"\n<strong>输出：</strong>\"AB\"\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>str1 = \"LEET\", str2 = \"CODE\"\n<strong>输出：</strong>\"\"\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= str1.length, str2.length &lt;= 1000</code></li>\n\t<li><code>str1</code>&nbsp;和&nbsp;<code>str2</code>&nbsp;由大写英文字母组成</li>\n</ul>\n",
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                "The greatest common divisor must be a prefix of each string, so we can try all prefixes."
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