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leetcode-problemset/leetcode-cn/originData/first-completely-painted-row-or-column.json
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"question": {
"questionId": "2685",
"questionFrontendId": "2661",
"categoryTitle": "Algorithms",
"boundTopicId": 2249459,
"title": "First Completely Painted Row or Column",
"titleSlug": "first-completely-painted-row-or-column",
"content": "<p>You are given a <strong>0-indexed</strong> integer array <code>arr</code>, and an <code>m x n</code> integer <strong>matrix</strong> <code>mat</code>. <code>arr</code> and <code>mat</code> both contain <strong>all</strong> the integers in the range <code>[1, m * n]</code>.</p>\n\n<p>Go through each index <code>i</code> in <code>arr</code> starting from index <code>0</code> and paint the cell in <code>mat</code> containing the integer <code>arr[i]</code>.</p>\n\n<p>Return <em>the smallest index</em> <code>i</code> <em>at which either a row or a column will be completely painted in</em> <code>mat</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"image explanation for example 1\" /><img alt=\"image explanation for example 1\" src=\"https://assets.leetcode.com/uploads/2023/01/18/grid1.jpg\" style=\"width: 321px; height: 81px;\" />\n<pre>\n<strong>Input:</strong> arr = [1,3,4,2], mat = [[1,4],[2,3]]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> The moves are shown in order, and both the first row and second column of the matrix become fully painted at arr[2].\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"image explanation for example 2\" src=\"https://assets.leetcode.com/uploads/2023/01/18/grid2.jpg\" style=\"width: 601px; height: 121px;\" />\n<pre>\n<strong>Input:</strong> arr = [2,8,7,4,1,3,5,6,9], mat = [[3,2,5],[1,4,6],[8,7,9]]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> The second column becomes fully painted at arr[3].\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == mat.length</code></li>\n\t<li><code>n = mat[i].length</code></li>\n\t<li><code>arr.length == m * n</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= m * n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= arr[i], mat[r][c] &lt;= m * n</code></li>\n\t<li>All the integers of <code>arr</code> are <strong>unique</strong>.</li>\n\t<li>All the integers of <code>mat</code> are <strong>unique</strong>.</li>\n</ul>\n",
"translatedTitle": "找出叠涂元素",
"translatedContent": "<p>给你一个下标从 <strong>0</strong> 开始的整数数组 <code>arr</code> 和一个 <code>m x n</code> 的整数 <strong>矩阵</strong> <code>mat</code> 。<code>arr</code> 和 <code>mat</code> 都包含范围 <code>[1m * n]</code> 内的 <strong>所有</strong> 整数。</p>\n\n<p>从下标 <code>0</code> 开始遍历 <code>arr</code> 中的每个下标 <code>i</code> ,并将包含整数 <code>arr[i]</code> 的 <code>mat</code> 单元格涂色。</p>\n\n<p>请你找出 <code>arr</code> 中在 <code>mat</code> 的某一行或某一列上都被涂色且下标最小的元素,并返回其下标 <code>i</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n<img alt=\"image explanation for example 1\" src=\"https://assets.leetcode.com/uploads/2023/01/18/grid1.jpg\" style=\"width: 321px; height: 81px;\" />\n<pre>\n<strong>输入:</strong>arr = [1,3,4,2], mat = [[1,4],[2,3]]\n<strong>输出:</strong>2\n<strong>解释:</strong>遍历如上图所示arr[2] 在矩阵中的第一行或第二列上都被涂色。\n</pre>\n\n<p><strong>示例 2</strong></p>\n<img alt=\"image explanation for example 2\" src=\"https://assets.leetcode.com/uploads/2023/01/18/grid2.jpg\" style=\"width: 601px; height: 121px;\" />\n<pre>\n<strong>输入:</strong>arr = [2,8,7,4,1,3,5,6,9], mat = [[3,2,5],[1,4,6],[8,7,9]]\n<strong>输出:</strong>3\n<strong>解释:</strong>遍历如上图所示arr[3] 在矩阵中的第二列上都被涂色。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>m == mat.length</code></li>\n\t<li><code>n = mat[i].length</code></li>\n\t<li><code>arr.length == m * n</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= m * n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= arr[i], mat[r][c] &lt;= m * n</code></li>\n\t<li><code>arr</code> 中的所有整数 <strong>互不相同</strong></li>\n\t<li><code>mat</code> 中的所有整数 <strong>互不相同</strong></li>\n</ul>\n",
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"hints": [
"Can we use a frequency array?",
"Pre-process the positions of the values in the matrix.",
"Traverse the array and increment the corresponding row and column frequency using the pre-processed positions.",
"If the row frequency becomes equal to the number of columns, or vice-versa return the current index."
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