leetcode-problemset/leetcode-cn/originData/final-value-of-variable-after-performing-operations.json

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        "question": {
            "questionId": "2137",
            "questionFrontendId": "2011",
            "categoryTitle": "Algorithms",
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            "title": "Final Value of Variable After Performing Operations",
            "titleSlug": "final-value-of-variable-after-performing-operations",
            "content": "<p>There is a programming language with only <strong>four</strong> operations and <strong>one</strong> variable <code>X</code>:</p>\n\n<ul>\n\t<li><code>++X</code> and <code>X++</code> <strong>increments</strong> the value of the variable <code>X</code> by <code>1</code>.</li>\n\t<li><code>--X</code> and <code>X--</code> <strong>decrements</strong> the value of the variable <code>X</code> by <code>1</code>.</li>\n</ul>\n\n<p>Initially, the value of <code>X</code> is <code>0</code>.</p>\n\n<p>Given an array of strings <code>operations</code> containing a list of operations, return <em>the <strong>final </strong>value of </em><code>X</code> <em>after performing all the operations</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> operations = [&quot;--X&quot;,&quot;X++&quot;,&quot;X++&quot;]\n<strong>Output:</strong> 1\n<strong>Explanation:</strong>&nbsp;The operations are performed as follows:\nInitially, X = 0.\n--X: X is decremented by 1, X =  0 - 1 = -1.\nX++: X is incremented by 1, X = -1 + 1 =  0.\nX++: X is incremented by 1, X =  0 + 1 =  1.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> operations = [&quot;++X&quot;,&quot;++X&quot;,&quot;X++&quot;]\n<strong>Output:</strong> 3\n<strong>Explanation: </strong>The operations are performed as follows:\nInitially, X = 0.\n++X: X is incremented by 1, X = 0 + 1 = 1.\n++X: X is incremented by 1, X = 1 + 1 = 2.\nX++: X is incremented by 1, X = 2 + 1 = 3.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> operations = [&quot;X++&quot;,&quot;++X&quot;,&quot;--X&quot;,&quot;X--&quot;]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong>&nbsp;The operations are performed as follows:\nInitially, X = 0.\nX++: X is incremented by 1, X = 0 + 1 = 1.\n++X: X is incremented by 1, X = 1 + 1 = 2.\n--X: X is decremented by 1, X = 2 - 1 = 1.\nX--: X is decremented by 1, X = 1 - 1 = 0.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= operations.length &lt;= 100</code></li>\n\t<li><code>operations[i]</code> will be either <code>&quot;++X&quot;</code>, <code>&quot;X++&quot;</code>, <code>&quot;--X&quot;</code>, or <code>&quot;X--&quot;</code>.</li>\n</ul>\n",
            "translatedTitle": "执行操作后的变量值",
            "translatedContent": "<p>存在一种仅支持 4 种操作和 1 个变量 <code>X</code> 的编程语言：</p>\n\n<ul>\n\t<li><code>++X</code> 和 <code>X++</code> 使变量 <code>X</code> 的值 <strong>加</strong> <code>1</code></li>\n\t<li><code>--X</code> 和 <code>X--</code> 使变量 <code>X</code> 的值 <strong>减</strong> <code>1</code></li>\n</ul>\n\n<p>最初，<code>X</code> 的值是 <code>0</code></p>\n\n<p>给你一个字符串数组 <code>operations</code> ，这是由操作组成的一个列表，返回执行所有操作后，<em> </em><code>X</code> 的 <strong>最终值</strong> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>operations = [\"--X\",\"X++\",\"X++\"]\n<strong>输出：</strong>1\n<strong>解释：</strong>操作按下述步骤执行：\n最初，X = 0\n--X：X 减 1 ，X =  0 - 1 = -1\nX++：X 加 1 ，X = -1 + 1 =  0\nX++：X 加 1 ，X =  0 + 1 =  1\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>operations = [\"++X\",\"++X\",\"X++\"]\n<strong>输出：</strong>3\n<strong>解释：</strong>操作按下述步骤执行： \n最初，X = 0\n++X：X 加 1 ，X = 0 + 1 = 1\n++X：X 加 1 ，X = 1 + 1 = 2\nX++：X 加 1 ，X = 2 + 1 = 3\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>operations = [\"X++\",\"++X\",\"--X\",\"X--\"]\n<strong>输出：</strong>0\n<strong>解释：</strong>操作按下述步骤执行：\n最初，X = 0\nX++：X 加 1 ，X = 0 + 1 = 1\n++X：X 加 1 ，X = 1 + 1 = 2\n--X：X 减 1 ，X = 2 - 1 = 1\nX--：X 减 1 ，X = 1 - 1 = 0\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= operations.length &lt;= 100</code></li>\n\t<li><code>operations[i]</code> 将会是 <code>\"++X\"</code>、<code>\"X++\"</code>、<code>\"--X\"</code> 或 <code>\"X--\"</code></li>\n</ul>\n",
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