leetcode-problemset/leetcode-cn/originData/earliest-possible-day-of-full-bloom.json

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            "title": "Earliest Possible Day of Full Bloom",
            "titleSlug": "earliest-possible-day-of-full-bloom",
            "content": "<p>You have <code>n</code> flower seeds. Every seed must be planted first before it can begin to grow, then bloom. Planting a seed takes time and so does the growth of a seed. You are given two <strong>0-indexed</strong> integer arrays <code>plantTime</code> and <code>growTime</code>, of length <code>n</code> each:</p>\n\n<ul>\n\t<li><code>plantTime[i]</code> is the number of <strong>full days</strong> it takes you to <strong>plant</strong> the <code>i<sup>th</sup></code> seed. Every day, you can work on planting exactly one seed. You <strong>do not</strong> have to work on planting the same seed on consecutive days, but the planting of a seed is not complete <strong>until</strong> you have worked <code>plantTime[i]</code> days on planting it in total.</li>\n\t<li><code>growTime[i]</code> is the number of <strong>full days</strong> it takes the <code>i<sup>th</sup></code> seed to grow after being completely planted. <strong>After</strong> the last day of its growth, the flower <strong>blooms</strong> and stays bloomed forever.</li>\n</ul>\n\n<p>From the beginning of day <code>0</code>, you can plant the seeds in <strong>any</strong> order.</p>\n\n<p>Return <em>the <strong>earliest</strong> possible day where <strong>all</strong> seeds are blooming</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/12/21/1.png\" style=\"width: 453px; height: 149px;\" />\n<pre>\n<strong>Input:</strong> plantTime = [1,4,3], growTime = [2,3,1]\n<strong>Output:</strong> 9\n<strong>Explanation:</strong> The grayed out pots represent planting days, colored pots represent growing days, and the flower represents the day it blooms.\nOne optimal way is:\nOn day 0, plant the 0<sup>th</sup> seed. The seed grows for 2 full days and blooms on day 3.\nOn days 1, 2, 3, and 4, plant the 1<sup>st</sup> seed. The seed grows for 3 full days and blooms on day 8.\nOn days 5, 6, and 7, plant the 2<sup>nd</sup> seed. The seed grows for 1 full day and blooms on day 9.\nThus, on day 9, all the seeds are blooming.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/12/21/2.png\" style=\"width: 454px; height: 184px;\" />\n<pre>\n<strong>Input:</strong> plantTime = [1,2,3,2], growTime = [2,1,2,1]\n<strong>Output:</strong> 9\n<strong>Explanation:</strong> The grayed out pots represent planting days, colored pots represent growing days, and the flower represents the day it blooms.\nOne optimal way is:\nOn day 1, plant the 0<sup>th</sup> seed. The seed grows for 2 full days and blooms on day 4.\nOn days 0 and 3, plant the 1<sup>st</sup> seed. The seed grows for 1 full day and blooms on day 5.\nOn days 2, 4, and 5, plant the 2<sup>nd</sup> seed. The seed grows for 2 full days and blooms on day 8.\nOn days 6 and 7, plant the 3<sup>rd</sup> seed. The seed grows for 1 full day and blooms on day 9.\nThus, on day 9, all the seeds are blooming.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> plantTime = [1], growTime = [1]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> On day 0, plant the 0<sup>th</sup> seed. The seed grows for 1 full day and blooms on day 2.\nThus, on day 2, all the seeds are blooming.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == plantTime.length == growTime.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= plantTime[i], growTime[i] &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
            "translatedTitle": "全部开花的最早一天",
            "translatedContent": "<p>你有 <code>n</code> 枚花的种子。每枚种子必须先种下，才能开始生长、开花。播种需要时间，种子的生长也是如此。给你两个下标从 <strong>0</strong> 开始的整数数组 <code>plantTime</code> 和 <code>growTime</code> ，每个数组的长度都是 <code>n</code> ：</p>\n\n<ul>\n\t<li><code>plantTime[i]</code> 是 <strong>播种</strong> 第 <code>i</code> 枚种子所需的 <strong>完整天数</strong> 。每天，你只能为播种某一枚种子而劳作。<strong>无须</strong> 连续几天都在种同一枚种子，但是种子播种必须在你工作的天数达到 <code>plantTime[i]</code> 之后才算完成。</li>\n\t<li><code>growTime[i]</code> 是第 <code>i</code> 枚种子完全种下后生长所需的 <strong>完整天数 </strong>。在它生长的最后一天 <strong>之后</strong> ，将会开花并且永远 <strong>绽放</strong> 。</li>\n</ul>\n\n<p>从第 <code>0</code> 开始，你可以按 <strong>任意</strong> 顺序播种种子。</p>\n\n<p>返回所有种子都开花的 <strong>最早</strong> 一天是第几天。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/12/21/1.png\" style=\"width: 453px; height: 149px;\">\n<pre><strong>输入：</strong>plantTime = [1,4,3], growTime = [2,3,1]\n<strong>输出：</strong>9\n<strong>解释：</strong>灰色的花盆表示播种的日子，彩色的花盆表示生长的日子，花朵表示开花的日子。\n一种最优方案是：\n第 0 天，播种第 0 枚种子，种子生长 2 整天。并在第 3 天开花。\n第 1、2、3、4 天，播种第 1 枚种子。种子生长 3 整天，并在第 8 天开花。\n第 5、6、7 天，播种第 2 枚种子。种子生长 1 整天，并在第 9 天开花。\n因此，在第 9 天，所有种子都开花。 \n</pre>\n\n<p><strong>示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/12/21/2.png\" style=\"width: 454px; height: 184px;\">\n<pre><strong>输入：</strong>plantTime = [1,2,3,2], growTime = [2,1,2,1]\n<strong>输出：</strong>9\n<strong>解释：</strong>灰色的花盆表示播种的日子，彩色的花盆表示生长的日子，花朵表示开花的日子。 \n一种最优方案是：\n第 1 天，播种第 0 枚种子，种子生长 2 整天。并在第 4 天开花。\n第 0、3 天，播种第 1 枚种子。种子生长 1 整天，并在第 5 天开花。\n第 2、4、5 天，播种第 2 枚种子。种子生长 2 整天，并在第 8 天开花。\n第 6、7 天，播种第 3 枚种子。种子生长 1 整天，并在第 9 天开花。\n因此，在第 9 天，所有种子都开花。 \n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>plantTime = [1], growTime = [1]\n<strong>输出：</strong>2\n<strong>解释：</strong>第 0 天，播种第 0 枚种子。种子需要生长 1 整天，然后在第 2 天开花。\n因此，在第 2 天，所有种子都开花。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == plantTime.length == growTime.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= plantTime[i], growTime[i] &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
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                "List the planting like the diagram above shows, where a row represents the timeline of a seed. A row i is above another row j if the last day planting seed i is ahead of the last day for seed j. Does it have any advantage to spend some days to plant seed j before completely planting seed i?",
                "No. It does not help seed j but could potentially delay the completion of seed i, resulting in a worse final answer. Remaining focused is a part of the optimal solution.",
                "Sort the seeds by their growTime in descending order. Can you prove why this strategy is the other part of the optimal solution? Note the bloom time of a seed is the sum of plantTime of all seeds preceding this seed plus the growTime of this seed.",
                "There is no way to improve this strategy. The seed to bloom last dominates the final answer. Exchanging the planting of this seed with another seed with either a larger or smaller growTime will result in a potentially worse answer."
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1.17<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 <a href=\\\"https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods\\\" target=\\\"_blank\\\">https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.10<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 \\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u9700\\u4f7f\\u7528 Map\\/TreeMap \\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"http:\\/\\/www.grantjenks.com\\/docs\\/sortedcontainers\\/\\\" target=\\\"_blank\\\">sortedcontainers<\\/a> \\u5e93\\u3002<\\/p>\"],\"scala\":[\"Scala\",\"<p>\\u7248\\u672c\\uff1a<code>Scala 2.13<\\/code><\\/p>\"],\"kotlin\":[\"Kotlin\",\"<p>\\u7248\\u672c\\uff1a<code>Kotlin 1.3.10<\\/code><\\/p>\"],\"rust\":[\"Rust\",\"<p>\\u7248\\u672c\\uff1a<code>rust 1.58.1<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 crates.io \\u7684 <a href=\\\"https:\\/\\/crates.io\\/crates\\/rand\\\" target=\\\"_blank\\\">rand<\\/a><\\/p>\"],\"php\":[\"PHP\",\"<p><code>PHP 8.1<\\/code>.<\\/p>\\r\\n\\r\\n<p>With bcmath module.<\\/p>\"],\"typescript\":[\"TypeScript\",\"<p>TypeScript 4.5.4<\\/p>\\r\\n\\r\\n<p>Compile Options: --alwaysStrict --strictBindCallApply --strictFunctionTypes --target ES2020<\\/p>\"],\"racket\":[\"Racket\",\"<p><a href=\\\"https:\\/\\/docs.racket-lang.org\\/guide\\/performance.html#%28tech._c%29\\\" target=\\\"_blank\\\">Racket CS<\\/a> v8.3<\\/p>\\r\\n\\r\\n<p>\\u4f7f\\u7528 #lang racket<\\/p>\\r\\n\\r\\n<p>\\u5df2\\u9884\\u5148 (require data\\/gvector data\\/queue data\\/order data\\/heap). \\u82e5\\u9700\\u4f7f\\u7528\\u5176\\u5b83\\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u53ef\\u81ea\\u884c require\\u3002<\\/p>\"],\"erlang\":[\"Erlang\",\"Erlang\\/OTP 24.2\"],\"elixir\":[\"Elixir\",\"Elixir 1.13.0 with Erlang\\/OTP 24.2\"]}",
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