mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
168 lines
20 KiB
JSON
168 lines
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"title": "Distinct Subsequences",
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"content": "<p>Given two strings <code>s</code> and <code>t</code>, return <em>the number of distinct subsequences of <code>s</code> which equals <code>t</code></em>.</p>\n\n<p>A string's <strong>subsequence</strong> is a new string formed from the original string by deleting some (can be none) of the characters without disturbing the remaining characters' relative positions. (i.e., <code>"ACE"</code> is a subsequence of <code>"ABCDE"</code> while <code>"AEC"</code> is not).</p>\n\n<p>The test cases are generated so that the answer fits on a 32-bit signed integer.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "rabbbit", t = "rabbit"\n<strong>Output:</strong> 3\n<strong>Explanation:</strong>\nAs shown below, there are 3 ways you can generate "rabbit" from S.\n<code><strong><u>rabb</u></strong>b<strong><u>it</u></strong></code>\n<code><strong><u>ra</u></strong>b<strong><u>bbit</u></strong></code>\n<code><strong><u>rab</u></strong>b<strong><u>bit</u></strong></code>\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "babgbag", t = "bag"\n<strong>Output:</strong> 5\n<strong>Explanation:</strong>\nAs shown below, there are 5 ways you can generate "bag" from S.\n<code><strong><u>ba</u></strong>b<u><strong>g</strong></u>bag</code>\n<code><strong><u>ba</u></strong>bgba<strong><u>g</u></strong></code>\n<code><u><strong>b</strong></u>abgb<strong><u>ag</u></strong></code>\n<code>ba<u><strong>b</strong></u>gb<u><strong>ag</strong></u></code>\n<code>babg<strong><u>bag</u></strong></code></pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length, t.length <= 1000</code></li>\n\t<li><code>s</code> and <code>t</code> consist of English letters.</li>\n</ul>\n",
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"translatedTitle": "不同的子序列",
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"translatedContent": "<p>给定一个字符串 <code>s</code><strong> </strong>和一个字符串 <code>t</code> ，计算在 <code>s</code> 的子序列中 <code>t</code> 出现的个数。</p>\n\n<p>字符串的一个 <strong>子序列</strong> 是指，通过删除一些（也可以不删除）字符且不干扰剩余字符相对位置所组成的新字符串。（例如，<code>\"ACE\"</code> 是 <code>\"ABCDE\"</code> 的一个子序列，而 <code>\"AEC\"</code> 不是）</p>\n\n<p>题目数据保证答案符合 32 位带符号整数范围。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"rabbbit\", t = \"rabbit\"<code>\n<strong>输出</strong></code><strong>：</strong><code>3\n</code><strong>解释：</strong>\n如下图所示, 有 3 种可以从 s 中得到 <code>\"rabbit\" 的方案</code>。\n<code><strong><u>rabb</u></strong>b<strong><u>it</u></strong></code>\n<code><strong><u>ra</u></strong>b<strong><u>bbit</u></strong></code>\n<code><strong><u>rab</u></strong>b<strong><u>bit</u></strong></code></pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"babgbag\", t = \"bag\"\n<code><strong>输出</strong></code><strong>：</strong><code>5\n</code><strong>解释：</strong>\n如下图所示, 有 5 种可以从 s 中得到 <code>\"bag\" 的方案</code>。 \n<code><strong><u>ba</u></strong>b<u><strong>g</strong></u>bag</code>\n<code><strong><u>ba</u></strong>bgba<strong><u>g</u></strong></code>\n<code><u><strong>b</strong></u>abgb<strong><u>ag</u></strong></code>\n<code>ba<u><strong>b</strong></u>gb<u><strong>ag</strong></u></code>\n<code>babg<strong><u>bag</u></strong></code>\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 <= s.length, t.length <= 1000</code></li>\n\t<li><code>s</code> 和 <code>t</code> 由英文字母组成</li>\n</ul>\n",
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