leetcode-problemset/leetcode-cn/originData/count-operations-to-obtain-zero.json

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            "title": "Count Operations to Obtain Zero",
            "titleSlug": "count-operations-to-obtain-zero",
            "content": "<p>You are given two <strong>non-negative</strong> integers <code>num1</code> and <code>num2</code>.</p>\n\n<p>In one <strong>operation</strong>, if <code>num1 &gt;= num2</code>, you must subtract <code>num2</code> from <code>num1</code>, otherwise subtract <code>num1</code> from <code>num2</code>.</p>\n\n<ul>\n\t<li>For example, if <code>num1 = 5</code> and <code>num2 = 4</code>, subtract <code>num2</code> from <code>num1</code>, thus obtaining <code>num1 = 1</code> and <code>num2 = 4</code>. However, if <code>num1 = 4</code> and <code>num2 = 5</code>, after one operation, <code>num1 = 4</code> and <code>num2 = 1</code>.</li>\n</ul>\n\n<p>Return <em>the <strong>number of operations</strong> required to make either</em> <code>num1 = 0</code> <em>or</em> <code>num2 = 0</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> num1 = 2, num2 = 3\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> \n- Operation 1: num1 = 2, num2 = 3. Since num1 &lt; num2, we subtract num1 from num2 and get num1 = 2, num2 = 3 - 2 = 1.\n- Operation 2: num1 = 2, num2 = 1. Since num1 &gt; num2, we subtract num2 from num1.\n- Operation 3: num1 = 1, num2 = 1. Since num1 == num2, we subtract num2 from num1.\nNow num1 = 0 and num2 = 1. Since num1 == 0, we do not need to perform any further operations.\nSo the total number of operations required is 3.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> num1 = 10, num2 = 10\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> \n- Operation 1: num1 = 10, num2 = 10. Since num1 == num2, we subtract num2 from num1 and get num1 = 10 - 10 = 0.\nNow num1 = 0 and num2 = 10. Since num1 == 0, we are done.\nSo the total number of operations required is 1.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= num1, num2 &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "得到 0 的操作数",
            "translatedContent": "<p>给你两个 <strong>非负</strong> 整数 <code>num1</code> 和 <code>num2</code> 。</p>\n\n<p>每一步 <strong>操作</strong>&nbsp;中，如果 <code>num1 &gt;= num2</code> ，你必须用 <code>num1</code> 减 <code>num2</code> ；否则，你必须用 <code>num2</code> 减 <code>num1</code> 。</p>\n\n<ul>\n\t<li>例如，<code>num1 = 5</code> 且 <code>num2 = 4</code> ，应该用&nbsp;<code>num1</code> 减 <code>num2</code> ，因此，得到 <code>num1 = 1</code> 和 <code>num2 = 4</code> 。然而，如果 <code>num1 = 4</code>且 <code>num2 = 5</code> ，一步操作后，得到 <code>num1 = 4</code> 和 <code>num2 = 1</code> 。</li>\n</ul>\n\n<p>返回使 <code>num1 = 0</code> 或 <code>num2 = 0</code> 的 <strong>操作数</strong> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>num1 = 2, num2 = 3\n<strong>输出：</strong>3\n<strong>解释：</strong>\n- 操作 1 ：num1 = 2 ，num2 = 3 。由于 num1 &lt; num2 ，num2 减 num1 得到 num1 = 2 ，num2 = 3 - 2 = 1 。\n- 操作 2 ：num1 = 2 ，num2 = 1 。由于 num1 &gt; num2 ，num1 减 num2 。\n- 操作 3 ：num1 = 1 ，num2 = 1 。由于 num1 == num2 ，num1 减 num2 。\n此时 num1 = 0 ，num2 = 1 。由于 num1 == 0 ，不需要再执行任何操作。\n所以总操作数是 3 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>num1 = 10, num2 = 10\n<strong>输出：</strong>1\n<strong>解释：</strong>\n- 操作 1 ：num1 = 10 ，num2 = 10 。由于 num1 == num2 ，num1 减 num2 得到 num1 = 10 - 10 = 0 。\n此时 num1 = 0 ，num2 = 10 。由于 num1 == 0 ，不需要再执行任何操作。\n所以总操作数是 1 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= num1, num2 &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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