leetcode-problemset/leetcode-cn/originData/bulb-switcher-ii.json

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            "title": "Bulb Switcher II",
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            "content": "<p>There is a room with <code>n</code> bulbs labeled from <code>1</code> to <code>n</code> that all are turned on initially, and <strong>four buttons</strong> on the wall. Each of the four buttons has a different functionality where:</p>\n\n<ul>\n\t<li><strong>Button 1:</strong> Flips the status of all the bulbs.</li>\n\t<li><strong>Button 2:</strong> Flips the status of all the bulbs with even labels (i.e., <code>2, 4, ...</code>).</li>\n\t<li><strong>Button 3:</strong> Flips the status of all the bulbs with odd labels (i.e., <code>1, 3, ...</code>).</li>\n\t<li><strong>Button 4:</strong> Flips the status of all the bulbs with a label <code>j = 3k + 1</code> where <code>k = 0, 1, 2, ...</code> (i.e., <code>1, 4, 7, 10, ...</code>).</li>\n</ul>\n\n<p>You must make <strong>exactly</strong> <code>presses</code> button presses in total. For each press, you may pick <strong>any</strong> of the four buttons to press.</p>\n\n<p>Given the two integers <code>n</code> and <code>presses</code>, return <em>the number of <strong>different possible statuses</strong> after performing all </em><code>presses</code><em> button presses</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 1, presses = 1\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> Status can be:\n- [off] by pressing button 1\n- [on] by pressing button 2\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 2, presses = 1\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> Status can be:\n- [off, off] by pressing button 1\n- [on, off] by pressing button 2\n- [off, on] by pressing button 3\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 3, presses = 1\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> Status can be:\n- [off, off, off] by pressing button 1\n- [off, on, off] by pressing button 2\n- [on, off, on] by pressing button 3\n- [off, on, on] by pressing button 4\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 1000</code></li>\n\t<li><code>0 &lt;= presses &lt;= 1000</code></li>\n</ul>\n",
            "translatedTitle": "灯泡开关 Ⅱ",
            "translatedContent": "<p>现有一个房间，墙上挂有&nbsp;<code>n</code>&nbsp;只已经打开的灯泡和 4 个按钮。在进行了&nbsp;<code>m</code>&nbsp;次未知操作后，你需要返回这&nbsp;<code>n</code>&nbsp;只灯泡可能有多少种不同的状态。</p>\n\n<p>假设这 <code>n</code> 只灯泡被编号为 [1, 2, 3 ..., n]，这 4 个按钮的功能如下：</p>\n\n<ol>\n\t<li>将所有灯泡的状态反转（即开变为关，关变为开）</li>\n\t<li>将编号为偶数的灯泡的状态反转</li>\n\t<li>将编号为奇数的灯泡的状态反转</li>\n\t<li>将编号为 <code>3k+1</code> 的灯泡的状态反转（k = 0, 1, 2, ...)</li>\n</ol>\n\n<p><strong>示例 1:</strong></p>\n\n<pre><strong>输入:</strong> n = 1, m = 1.\n<strong>输出:</strong> 2\n<strong>说明:</strong> 状态为: [开], [关]\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre><strong>输入:</strong> n = 2, m = 1.\n<strong>输出:</strong> 3\n<strong>说明:</strong> 状态为: [开, 关], [关, 开], [关, 关]\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre><strong>输入:</strong> n = 3, m = 1.\n<strong>输出:</strong> 4\n<strong>说明:</strong> 状态为: [关, 开, 关], [开, 关, 开], [关, 关, 关], [关, 开, 开].\n</pre>\n\n<p><strong>注意：</strong>&nbsp;<code>n</code>&nbsp;和&nbsp;<code>m</code> 都属于 [0, 1000].</p>\n",
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