mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-25 17:50:26 +08:00
198 lines
25 KiB
JSON
198 lines
25 KiB
JSON
{
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"questionId": "1000298",
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"questionFrontendId": "剑指 Offer II 045",
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"categoryTitle": "LCOF2",
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"boundTopicId": 910292,
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"title": "二叉树最底层最左边的值",
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"content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
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"translatedTitle": "二叉树最底层最左边的值",
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"translatedContent": "<p>给定一个二叉树的 <strong>根节点</strong> <code>root</code>，请找出该二叉树的 <strong>最底层 最左边 </strong>节点的值。</p>\n\n<p>假设二叉树中至少有一个节点。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<p><img src=\"https://assets.leetcode.com/uploads/2020/12/14/tree1.jpg\" style=\"width: 182px; \" /></p>\n\n<pre>\n<strong>输入: </strong>root = [2,1,3]\n<strong>输出: </strong>1\n</pre>\n\n<p><strong>示例 2: </strong></p>\n\n<p><img src=\"https://assets.leetcode.com/uploads/2020/12/14/tree2.jpg\" style=\"width: 242px; \" /><strong> </strong></p>\n\n<pre>\n<strong>输入: </strong>[1,2,3,4,null,5,6,null,null,7]\n<strong>输出: </strong>7\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>二叉树的节点个数的范围是 <code>[1,10<sup>4</sup>]</code></li>\n\t<li><meta charset=\"UTF-8\" /><code>-2<sup>31</sup> <= Node.val <= 2<sup>31</sup> - 1</code> </li>\n</ul>\n\n<p> </p>\n\n<p><meta charset=\"UTF-8\" />注意：本题与主站 513 题相同： <a href=\"https://leetcode-cn.com/problems/find-bottom-left-tree-value/\">https://leetcode-cn.com/problems/find-bottom-left-tree-value/</a></p>\n",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode() : val(0), left(nullptr), right(nullptr) {}\n * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n int findBottomLeftValue(TreeNode* root) {\n\n }\n};",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * int val;\n * TreeNode left;\n * TreeNode right;\n * TreeNode() {}\n * TreeNode(int val) { this.val = val; }\n * TreeNode(int val, TreeNode left, TreeNode right) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\nclass Solution {\n public int findBottomLeftValue(TreeNode root) {\n\n }\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution(object):\n def findBottomLeftValue(self, root):\n \"\"\"\n :type root: TreeNode\n :rtype: int\n \"\"\"",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public int FindBottomLeftValue(TreeNode root) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @return {number}\n */\nvar findBottomLeftValue = function(root) {\n\n};",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @return {Integer}\ndef find_bottom_left_value(root)\n\nend",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func findBottomLeftValue(_ root: TreeNode?) -> Int {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc findBottomLeftValue(root *TreeNode) int {\n\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def findBottomLeftValue(root: TreeNode): Int = {\n\n }\n}",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun findBottomLeftValue(root: TreeNode?): Int {\n\n }\n}",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn find_bottom_left_value(root: Option<Rc<RefCell<TreeNode>>>) -> i32 {\n\n }\n}",
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"code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec find_bottom_left_value(root :: TreeNode.t | nil) :: integer\n def find_bottom_left_value(root) do\n\n end\nend",
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