mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
180 lines
18 KiB
JSON
180 lines
18 KiB
JSON
{
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"questionId": "1000215",
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"questionFrontendId": "LCP 28",
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"categoryTitle": "Algorithms",
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"boundTopicId": 696158,
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"title": "采购方案",
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"titleSlug": "4xy4Wx",
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"content": "",
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"translatedTitle": "采购方案",
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"translatedContent": "小力将 N 个零件的报价存于数组 `nums`。小力预算为 `target`，假定小力仅购买两个零件，要求购买零件的花费不超过预算，请问他有多少种采购方案。\n\n注意：答案需要以 `1e9 + 7 (1000000007)` 为底取模，如：计算初始结果为：`1000000008`，请返回 `1`\n\n\n**示例 1：**\n>输入：`nums = [2,5,3,5], target = 6`\n>\n>输出：`1`\n>\n>解释：预算内仅能购买 nums[0] 与 nums[2]。\n\n**示例 2：**\n>输入：`nums = [2,2,1,9], target = 10`\n>\n>输出：`4`\n>\n>解释：符合预算的采购方案如下：\n>nums[0] + nums[1] = 4\n>nums[0] + nums[2] = 3\n>nums[1] + nums[2] = 3\n>nums[2] + nums[3] = 10\n\n**提示：**\n- `2 <= nums.length <= 10^5`\n- `1 <= nums[i], target <= 10^5`\n",
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"isPaidOnly": false,
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"difficulty": "Easy",
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"code": "class Solution {\npublic:\n int purchasePlans(vector<int>& nums, int target) {\n\n }\n};",
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"code": "class Solution(object):\n def purchasePlans(self, nums, target):\n \"\"\"\n :type nums: List[int]\n :type target: int\n :rtype: int\n \"\"\"",
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"code": "# @param {Integer[]} nums\n# @param {Integer} target\n# @return {Integer}\ndef purchase_plans(nums, target)\n\nend",
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