mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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174 lines
18 KiB
JSON
174 lines
18 KiB
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"content": "<p>You are given <code>n</code> tasks labeled from <code>0</code> to <code>n - 1</code> represented by a 2D integer array <code>tasks</code>, where <code>tasks[i] = [enqueueTime<sub>i</sub>, processingTime<sub>i</sub>]</code> means that the <code>i<sup>th</sup></code> task will be available to process at <code>enqueueTime<sub>i</sub></code> and will take <code>processingTime<sub>i</sub></code><sub> </sub>to finish processing.</p>\n\n<p>You have a single-threaded CPU that can process <strong>at most one</strong> task at a time and will act in the following way:</p>\n\n<ul>\n\t<li>If the CPU is idle and there are no available tasks to process, the CPU remains idle.</li>\n\t<li>If the CPU is idle and there are available tasks, the CPU will choose the one with the <strong>shortest processing time</strong>. If multiple tasks have the same shortest processing time, it will choose the task with the smallest index.</li>\n\t<li>Once a task is started, the CPU will <strong>process the entire task</strong> without stopping.</li>\n\t<li>The CPU can finish a task then start a new one instantly.</li>\n</ul>\n\n<p>Return <em>the order in which the CPU will process the tasks.</em></p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> tasks = [[1,2],[2,4],[3,2],[4,1]]\n<strong>Output:</strong> [0,2,3,1]\n<strong>Explanation: </strong>The events go as follows: \n- At time = 1, task 0 is available to process. Available tasks = {0}.\n- Also at time = 1, the idle CPU starts processing task 0. Available tasks = {}.\n- At time = 2, task 1 is available to process. Available tasks = {1}.\n- At time = 3, task 2 is available to process. Available tasks = {1, 2}.\n- Also at time = 3, the CPU finishes task 0 and starts processing task 2 as it is the shortest. Available tasks = {1}.\n- At time = 4, task 3 is available to process. Available tasks = {1, 3}.\n- At time = 5, the CPU finishes task 2 and starts processing task 3 as it is the shortest. Available tasks = {1}.\n- At time = 6, the CPU finishes task 3 and starts processing task 1. Available tasks = {}.\n- At time = 10, the CPU finishes task 1 and becomes idle.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> tasks = [[7,10],[7,12],[7,5],[7,4],[7,2]]\n<strong>Output:</strong> [4,3,2,0,1]\n<strong>Explanation</strong><strong>: </strong>The events go as follows:\n- At time = 7, all the tasks become available. Available tasks = {0,1,2,3,4}.\n- Also at time = 7, the idle CPU starts processing task 4. Available tasks = {0,1,2,3}.\n- At time = 9, the CPU finishes task 4 and starts processing task 3. Available tasks = {0,1,2}.\n- At time = 13, the CPU finishes task 3 and starts processing task 2. Available tasks = {0,1}.\n- At time = 18, the CPU finishes task 2 and starts processing task 0. Available tasks = {1}.\n- At time = 28, the CPU finishes task 0 and starts processing task 1. Available tasks = {}.\n- At time = 40, the CPU finishes task 1 and becomes idle.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>tasks.length == n</code></li>\n\t<li><code>1 <= n <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= enqueueTime<sub>i</sub>, processingTime<sub>i</sub> <= 10<sup>9</sup></code></li>\n</ul>\n",
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"To simulate the problem we first need to note that if at any point in time there are no enqueued tasks we need to wait to the smallest enqueue time of a non-processed element",
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"We need a data structure like a min-heap to support choosing the task with the smallest processing time from all the enqueued tasks"
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