mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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186 lines
22 KiB
JSON
186 lines
22 KiB
JSON
{
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"data": {
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"question": {
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"questionId": "2461",
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"questionFrontendId": "2385",
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"boundTopicId": null,
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"title": "Amount of Time for Binary Tree to Be Infected",
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"titleSlug": "amount-of-time-for-binary-tree-to-be-infected",
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"content": "<p>You are given the <code>root</code> of a binary tree with <strong>unique</strong> values, and an integer <code>start</code>. At minute <code>0</code>, an <strong>infection</strong> starts from the node with value <code>start</code>.</p>\n\n<p>Each minute, a node becomes infected if:</p>\n\n<ul>\n\t<li>The node is currently uninfected.</li>\n\t<li>The node is adjacent to an infected node.</li>\n</ul>\n\n<p>Return <em>the number of minutes needed for the entire tree to be infected.</em></p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/06/25/image-20220625231744-1.png\" style=\"width: 400px; height: 306px;\" />\n<pre>\n<strong>Input:</strong> root = [1,5,3,null,4,10,6,9,2], start = 3\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> The following nodes are infected during:\n- Minute 0: Node 3\n- Minute 1: Nodes 1, 10 and 6\n- Minute 2: Node 5\n- Minute 3: Node 4\n- Minute 4: Nodes 9 and 2\nIt takes 4 minutes for the whole tree to be infected so we return 4.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/06/25/image-20220625231812-2.png\" style=\"width: 75px; height: 66px;\" />\n<pre>\n<strong>Input:</strong> root = [1], start = 1\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> At minute 0, the only node in the tree is infected so we return 0.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[1, 10<sup>5</sup>]</code>.</li>\n\t<li><code>1 <= Node.val <= 10<sup>5</sup></code></li>\n\t<li>Each node has a <strong>unique</strong> value.</li>\n\t<li>A node with a value of <code>start</code> exists in the tree.</li>\n</ul>\n",
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"difficulty": "Medium",
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"similarQuestions": "[{\"title\": \"Maximum Depth of Binary Tree\", \"titleSlug\": \"maximum-depth-of-binary-tree\", \"difficulty\": \"Easy\", \"translatedTitle\": null}, {\"title\": \"Shortest Path to Get Food\", \"titleSlug\": \"shortest-path-to-get-food\", \"difficulty\": \"Medium\", \"translatedTitle\": null}, {\"title\": \"All Nodes Distance K in Binary Tree\", \"titleSlug\": \"all-nodes-distance-k-in-binary-tree\", \"difficulty\": \"Medium\", \"translatedTitle\": null}]",
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"exampleTestcases": "[1,5,3,null,4,10,6,9,2]\n3\n[1]\n1",
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"categoryTitle": "Algorithms",
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"contributors": [],
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{
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"name": "Tree",
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"name": "Depth-First Search",
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"name": "Breadth-First Search",
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"name": "Binary Tree",
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"slug": "binary-tree",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode() : val(0), left(nullptr), right(nullptr) {}\n * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n int amountOfTime(TreeNode* root, int start) {\n \n }\n};",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * int val;\n * TreeNode left;\n * TreeNode right;\n * TreeNode() {}\n * TreeNode(int val) { this.val = val; }\n * TreeNode(int val, TreeNode left, TreeNode right) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\nclass Solution {\n public int amountOfTime(TreeNode root, int start) {\n \n }\n}",
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{
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"lang": "Python",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution(object):\n def amountOfTime(self, root, start):\n \"\"\"\n :type root: Optional[TreeNode]\n :type start: int\n :rtype: int\n \"\"\"\n ",
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"code": "# Definition for a binary tree node.\n# class TreeNode:\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution:\n def amountOfTime(self, root: Optional[TreeNode], start: int) -> int:\n ",
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"lang": "C",
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"langSlug": "c",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * struct TreeNode *left;\n * struct TreeNode *right;\n * };\n */\n\n\nint amountOfTime(struct TreeNode* root, int start){\n\n}",
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{
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"lang": "C#",
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"langSlug": "csharp",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public int AmountOfTime(TreeNode root, int start) {\n \n }\n}",
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"__typename": "CodeSnippetNode"
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"lang": "JavaScript",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @param {number} start\n * @return {number}\n */\nvar amountOfTime = function(root, start) {\n \n};",
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"lang": "Ruby",
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"langSlug": "ruby",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @param {Integer} start\n# @return {Integer}\ndef amount_of_time(root, start)\n \nend",
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"lang": "Swift",
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"langSlug": "swift",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func amountOfTime(_ root: TreeNode?, _ start: Int) -> Int {\n \n }\n}",
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"lang": "Go",
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"langSlug": "golang",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc amountOfTime(root *TreeNode, start int) int {\n \n}",
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"lang": "Scala",
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"langSlug": "scala",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def amountOfTime(root: TreeNode, start: Int): Int = {\n \n }\n}",
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"lang": "Kotlin",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun amountOfTime(root: TreeNode?, start: Int): Int {\n \n }\n}",
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{
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"lang": "Rust",
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"langSlug": "rust",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n// \n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn amount_of_time(root: Option<Rc<RefCell<TreeNode>>>, start: i32) -> i32 {\n \n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @param Integer $start\n * @return Integer\n */\n function amountOfTime($root, $start) {\n \n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction amountOfTime(root: TreeNode | null, start: number): number {\n\n};",
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"langSlug": "racket",
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"code": "; Definition for a binary tree node.\n#|\n\n; val : integer?\n; left : (or/c tree-node? #f)\n; right : (or/c tree-node? #f)\n(struct tree-node\n (val left right) #:mutable #:transparent)\n\n; constructor\n(define (make-tree-node [val 0])\n (tree-node val #f #f))\n\n|#\n\n(define/contract (amount-of-time root start)\n (-> (or/c tree-node? #f) exact-integer? exact-integer?)\n\n )",
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"code": "%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%% left = null :: 'null' | #tree_node{},\n%% right = null :: 'null' | #tree_node{}}).\n\n-spec amount_of_time(Root :: #tree_node{} | null, Start :: integer()) -> integer().\namount_of_time(Root, Start) ->\n .",
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"code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec amount_of_time(root :: TreeNode.t | nil, start :: integer) :: integer\n def amount_of_time(root, start) do\n\n end\nend",
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"Convert the tree to an undirected graph to make it easier to handle.",
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"Use BFS starting at the start node to find the distance between each node and the start node. The answer is the maximum distance."
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],
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Java 8 features such as lambda expressions and stream API can be used. </p>\\r\\n\\r\\n<p>Most standard library headers are already included automatically for your convenience.</p>\\r\\n<p>Includes <code>Pair</code> class from https://docs.oracle.com/javase/8/javafx/api/javafx/util/Pair.html.</p>\"], \"python\": [\"Python\", \"<p><code>Python 2.7.12</code>.</p>\\r\\n\\r\\n<p>Most libraries are already imported automatically for your convenience, such as <a href=\\\"https://docs.python.org/2/library/array.html\\\" target=\\\"_blank\\\">array</a>, <a href=\\\"https://docs.python.org/2/library/bisect.html\\\" target=\\\"_blank\\\">bisect</a>, <a href=\\\"https://docs.python.org/2/library/collections.html\\\" target=\\\"_blank\\\">collections</a>. 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Adding an item to a hash.</b>\\r\\n<pre>\\r\\nstruct hash_entry {\\r\\n int id; /* we'll use this field as the key */\\r\\n char name[10];\\r\\n UT_hash_handle hh; /* makes this structure hashable */\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry *s) {\\r\\n HASH_ADD_INT(users, id, s);\\r\\n}\\r\\n</pre>\\r\\n</p>\\r\\n\\r\\n<p><b>2. Looking up an item in a hash:</b>\\r\\n<pre>\\r\\nstruct hash_entry *find_user(int user_id) {\\r\\n struct hash_entry *s;\\r\\n HASH_FIND_INT(users, &user_id, s);\\r\\n return s;\\r\\n}\\r\\n</pre>\\r\\n</p>\\r\\n\\r\\n<p><b>3. 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"libraryUrl": null,
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"adminUrl": null,
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"challengeQuestion": null,
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"__typename": "QuestionNode"
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}
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}
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} |