leetcode-problemset/leetcode-cn/originData/split-the-array.json

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        "question": {
            "questionId": "3324",
            "questionFrontendId": "3046",
            "categoryTitle": "Algorithms",
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            "title": "Split the Array",
            "titleSlug": "split-the-array",
            "content": "<p>You are given an integer array <code>nums</code> of <strong>even</strong> length. You have to split the array into two parts <code>nums1</code> and <code>nums2</code> such that:</p>\n\n<ul>\n\t<li><code>nums1.length == nums2.length == nums.length / 2</code>.</li>\n\t<li><code>nums1</code> should contain <strong>distinct </strong>elements.</li>\n\t<li><code>nums2</code> should also contain <strong>distinct</strong> elements.</li>\n</ul>\n\n<p>Return <code>true</code><em> if it is possible to split the array, and </em><code>false</code> <em>otherwise</em><em>.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,1,2,2,3,4]\n<strong>Output:</strong> true\n<strong>Explanation:</strong> One of the possible ways to split nums is nums1 = [1,2,3] and nums2 = [1,2,4].\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,1,1,1]\n<strong>Output:</strong> false\n<strong>Explanation:</strong> The only possible way to split nums is nums1 = [1,1] and nums2 = [1,1]. Both nums1 and nums2 do not contain distinct elements. Therefore, we return false.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 100</code></li>\n\t<li><code>nums.length % 2 == 0 </code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 100</code></li>\n</ul>\n",
            "translatedTitle": "分割数组",
            "translatedContent": "<p>给你一个长度为 <strong>偶数 </strong>的整数数组 <code>nums</code> 。你需要将这个数组分割成 <code>nums1</code> 和 <code>nums2</code> 两部分，要求：</p>\n\n<ul>\n\t<li><code>nums1.length == nums2.length == nums.length / 2</code> 。</li>\n\t<li><code>nums1</code> 应包含 <strong>互不相同</strong><strong> </strong>的元素。</li>\n\t<li><code>nums2</code>也应包含<strong> 互不相同</strong> 的元素。</li>\n</ul>\n\n<p>如果能够分割数组就返回 <code>true</code> ，否则返回 <code>false</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,1,2,2,3,4]\n<strong>输出：</strong>true\n<strong>解释：</strong>分割 nums 的可行方案之一是 nums1 = [1,2,3] 和 nums2 = [1,2,4] 。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,1,1,1]\n<strong>输出：</strong>false\n<strong>解释：</strong>分割 nums 的唯一可行方案是 nums1 = [1,1] 和 nums2 = [1,1] 。但 nums1 和 nums2 都不是由互不相同的元素构成。因此，返回 false 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 100</code></li>\n\t<li><code>nums.length % 2 == 0</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 100</code></li>\n</ul>\n",
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                "It’s impossible if the same number occurs more than twice. So just check the frequency of each value."
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