leetcode-problemset/leetcode-cn/originData/find-the-xor-of-numbers-which-appear-twice.json

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            "categoryTitle": "Algorithms",
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            "title": "Find the XOR of Numbers Which Appear Twice",
            "titleSlug": "find-the-xor-of-numbers-which-appear-twice",
            "content": "<p>You are given an array <code>nums</code>, where each number in the array appears <strong>either</strong><em> </em>once<em> </em>or<em> </em>twice.</p>\n\n<p>Return the bitwise<em> </em><code>XOR</code> of all the numbers that appear twice in the array, or 0 if no number appears twice.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [1,2,1,3]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">1</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The only number that appears twice in&nbsp;<code>nums</code>&nbsp;is 1.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [1,2,3]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>No number appears twice in&nbsp;<code>nums</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [1,2,2,1]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">3</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>Numbers 1 and 2 appeared twice. <code>1 XOR 2 == 3</code>.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 50</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 50</code></li>\n\t<li>Each number in <code>nums</code> appears either once or twice.</li>\n</ul>\n",
            "translatedTitle": "求出出现两次数字的 XOR 值",
            "translatedContent": "<p>给你一个数组&nbsp;<code>nums</code>&nbsp;，数组中的数字 <strong>要么</strong> 出现一次，<strong>要么</strong>&nbsp;出现两次。</p>\n\n<p>请你返回数组中所有出现两次数字的按位<em>&nbsp;</em><code>XOR</code>&nbsp;值，如果没有数字出现过两次，返回 0 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>nums = [1,2,1,3]</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>1</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p><code>nums</code>&nbsp;中唯一出现过两次的数字是 1 。</p>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>nums = [1,2,3]</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>0</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p><code>nums</code>&nbsp;中没有数字出现两次。</p>\n</div>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>nums = [1,2,2,1]</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>3</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>数字 1 和&nbsp;2 出现过两次。<code>1 XOR 2 == 3</code>&nbsp;。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 50</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 50</code></li>\n\t<li><code>nums</code>&nbsp;中每个数字要么出现过一次，要么出现过两次。</li>\n</ul>\n",
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