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leetcode-problemset/leetcode-cn/originData/apple-redistribution-into-boxes.json
2024-03-22 16:17:08 +08:00

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"question": {
"questionId": "3334",
"questionFrontendId": "3074",
"categoryTitle": "Algorithms",
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"title": "Apple Redistribution into Boxes",
"titleSlug": "apple-redistribution-into-boxes",
"content": "<p>You are given an array <code>apple</code> of size <code>n</code> and an array <code>capacity</code> of size <code>m</code>.</p>\n\n<p>There are <code>n</code> packs where the <code>i<sup>th</sup></code> pack contains <code>apple[i]</code> apples. There are <code>m</code> boxes as well, and the <code>i<sup>th</sup></code> box has a capacity of <code>capacity[i]</code> apples.</p>\n\n<p>Return <em>the <strong>minimum</strong> number of boxes you need to select to redistribute these </em><code>n</code><em> packs of apples into boxes</em>.</p>\n\n<p><strong>Note</strong> that, apples from the same pack can be distributed into different boxes.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> apple = [1,3,2], capacity = [4,3,1,5,2]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> We will use boxes with capacities 4 and 5.\nIt is possible to distribute the apples as the total capacity is greater than or equal to the total number of apples.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> apple = [5,5,5], capacity = [2,4,2,7]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> We will need to use all the boxes.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == apple.length &lt;= 50</code></li>\n\t<li><code>1 &lt;= m == capacity.length &lt;= 50</code></li>\n\t<li><code>1 &lt;= apple[i], capacity[i] &lt;= 50</code></li>\n\t<li>The input is generated such that it&#39;s possible to redistribute packs of apples into boxes.</li>\n</ul>\n",
"translatedTitle": "重新分装苹果",
"translatedContent": "<p>给你一个长度为 <code>n</code> 的数组 <code>apple</code> 和另一个长度为 <code>m</code> 的数组 <code>capacity</code> 。</p>\n\n<p>一共有 <code>n</code> 个包裹,其中第 <code>i</code> 个包裹中装着 <code>apple[i]</code> 个苹果。同时,还有 <code>m</code> 个箱子,第 <code>i</code> 个箱子的容量为 <code>capacity[i]</code> 个苹果。</p>\n\n<p>请你选择一些箱子来将这 <code>n</code> 个包裹中的苹果重新分装到箱子中,返回你需要选择的箱子的<strong> 最小</strong> 数量。</p>\n\n<p><strong>注意</strong>,同一个包裹中的苹果可以分装到不同的箱子中。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>apple = [1,3,2], capacity = [4,3,1,5,2]\n<strong>输出:</strong>2\n<strong>解释:</strong>使用容量为 4 和 5 的箱子。\n总容量大于或等于苹果的总数所以可以完成重新分装。\n</pre>\n\n<p><strong class=\"example\">示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>apple = [5,5,5], capacity = [2,4,2,7]\n<strong>输出:</strong>4\n<strong>解释:</strong>需要使用所有箱子。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == apple.length &lt;= 50</code></li>\n\t<li><code>1 &lt;= m == capacity.length &lt;= 50</code></li>\n\t<li><code>1 &lt;= apple[i], capacity[i] &lt;= 50</code></li>\n\t<li>输入数据保证可以将包裹中的苹果重新分装到箱子中。</li>\n</ul>\n",
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"Sort array <code>capacity</code> in non-decreasing order.",
"Select boxes greedily while the total capacity is smaller than the total number of apples."
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