mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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181 lines
17 KiB
JSON
181 lines
17 KiB
JSON
{
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"questionId": "2372",
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"title": "Rearrange Characters to Make Target String",
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"content": "<p>You are given two <strong>0-indexed</strong> strings <code>s</code> and <code>target</code>. You can take some letters from <code>s</code> and rearrange them to form new strings.</p>\n\n<p>Return<em> the <strong>maximum</strong> number of copies of </em><code>target</code><em> that can be formed by taking letters from </em><code>s</code><em> and rearranging them.</em></p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "ilovecodingonleetcode", target = "code"\n<strong>Output:</strong> 2\n<strong>Explanation:</strong>\nFor the first copy of "code", take the letters at indices 4, 5, 6, and 7.\nFor the second copy of "code", take the letters at indices 17, 18, 19, and 20.\nThe strings that are formed are "ecod" and "code" which can both be rearranged into "code".\nWe can make at most two copies of "code", so we return 2.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "abcba", target = "abc"\n<strong>Output:</strong> 1\n<strong>Explanation:</strong>\nWe can make one copy of "abc" by taking the letters at indices 0, 1, and 2.\nWe can make at most one copy of "abc", so we return 1.\nNote that while there is an extra 'a' and 'b' at indices 3 and 4, we cannot reuse the letter 'c' at index 2, so we cannot make a second copy of "abc".\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "abbaccaddaeea", target = "aaaaa"\n<strong>Output:</strong> 1\n<strong>Explanation:</strong>\nWe can make one copy of "aaaaa" by taking the letters at indices 0, 3, 6, 9, and 12.\nWe can make at most one copy of "aaaaa", so we return 1.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 100</code></li>\n\t<li><code>1 <= target.length <= 10</code></li>\n\t<li><code>s</code> and <code>target</code> consist of lowercase English letters.</li>\n</ul>\n",
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"code": "class Solution(object):\n def rearrangeCharacters(self, s, target):\n \"\"\"\n :type s: str\n :type target: str\n :rtype: int\n \"\"\"\n ",
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"code": "# @param {String} s\n# @param {String} target\n# @return {Integer}\ndef rearrange_characters(s, target)\n \nend",
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"code": "object Solution {\n def rearrangeCharacters(s: String, target: String): Int = {\n \n }\n}",
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"code": "impl Solution {\n pub fn rearrange_characters(s: String, target: String) -> i32 {\n \n }\n}",
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"code": "(define/contract (rearrange-characters s target)\n (-> string? string? exact-integer?)\n )",
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"code": "-spec rearrange_characters(S :: unicode:unicode_binary(), Target :: unicode:unicode_binary()) -> integer().\nrearrange_characters(S, Target) ->\n .",
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"code": "defmodule Solution do\n @spec rearrange_characters(s :: String.t, target :: String.t) :: integer\n def rearrange_characters(s, target) do\n \n end\nend",
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"hints": [
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"Count the frequency of each character in s and target.",
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"Consider each letter one at a time. If there are x occurrences of a letter in s and y occurrences of the same letter in target, how many copies of this letter can we make?",
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"We can make floor(x / y) copies of the letter."
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],
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"sampleTestCase": "\"ilovecodingonleetcode\"\n\"code\"",
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