mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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174 lines
20 KiB
JSON
174 lines
20 KiB
JSON
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"title": "Process Restricted Friend Requests",
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"content": "<p>You are given an integer <code>n</code> indicating the number of people in a network. Each person is labeled from <code>0</code> to <code>n - 1</code>.</p>\n\n<p>You are also given a <strong>0-indexed</strong> 2D integer array <code>restrictions</code>, where <code>restrictions[i] = [x<sub>i</sub>, y<sub>i</sub>]</code> means that person <code>x<sub>i</sub></code> and person <code>y<sub>i</sub></code> <strong>cannot </strong>become <strong>friends</strong>,<strong> </strong>either <strong>directly</strong> or <strong>indirectly</strong> through other people.</p>\n\n<p>Initially, no one is friends with each other. You are given a list of friend requests as a <strong>0-indexed</strong> 2D integer array <code>requests</code>, where <code>requests[j] = [u<sub>j</sub>, v<sub>j</sub>]</code> is a friend request between person <code>u<sub>j</sub></code> and person <code>v<sub>j</sub></code>.</p>\n\n<p>A friend request is <strong>successful </strong>if <code>u<sub>j</sub></code> and <code>v<sub>j</sub></code> can be <strong>friends</strong>. Each friend request is processed in the given order (i.e., <code>requests[j]</code> occurs before <code>requests[j + 1]</code>), and upon a successful request, <code>u<sub>j</sub></code> and <code>v<sub>j</sub></code> <strong>become direct friends</strong> for all future friend requests.</p>\n\n<p>Return <em>a <strong>boolean array</strong> </em><code>result</code>,<em> where each </em><code>result[j]</code><em> is </em><code>true</code><em> if the </em><code>j<sup>th</sup></code><em> friend request is <strong>successful</strong> or </em><code>false</code><em> if it is not</em>.</p>\n\n<p><strong>Note:</strong> If <code>u<sub>j</sub></code> and <code>v<sub>j</sub></code> are already direct friends, the request is still <strong>successful</strong>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 3, restrictions = [[0,1]], requests = [[0,2],[2,1]]\n<strong>Output:</strong> [true,false]\n<strong>Explanation:\n</strong>Request 0: Person 0 and person 2 can be friends, so they become direct friends. \nRequest 1: Person 2 and person 1 cannot be friends since person 0 and person 1 would be indirect friends (1--2--0).\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 3, restrictions = [[0,1]], requests = [[1,2],[0,2]]\n<strong>Output:</strong> [true,false]\n<strong>Explanation:\n</strong>Request 0: Person 1 and person 2 can be friends, so they become direct friends.\nRequest 1: Person 0 and person 2 cannot be friends since person 0 and person 1 would be indirect friends (0--2--1).\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 5, restrictions = [[0,1],[1,2],[2,3]], requests = [[0,4],[1,2],[3,1],[3,4]]\n<strong>Output:</strong> [true,false,true,false]\n<strong>Explanation:\n</strong>Request 0: Person 0 and person 4 can be friends, so they become direct friends.\nRequest 1: Person 1 and person 2 cannot be friends since they are directly restricted.\nRequest 2: Person 3 and person 1 can be friends, so they become direct friends.\nRequest 3: Person 3 and person 4 cannot be friends since person 0 and person 1 would be indirect friends (0--4--3--1).\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 <= n <= 1000</code></li>\n\t<li><code>0 <= restrictions.length <= 1000</code></li>\n\t<li><code>restrictions[i].length == 2</code></li>\n\t<li><code>0 <= x<sub>i</sub>, y<sub>i</sub> <= n - 1</code></li>\n\t<li><code>x<sub>i</sub> != y<sub>i</sub></code></li>\n\t<li><code>1 <= requests.length <= 1000</code></li>\n\t<li><code>requests[j].length == 2</code></li>\n\t<li><code>0 <= u<sub>j</sub>, v<sub>j</sub> <= n - 1</code></li>\n\t<li><code>u<sub>j</sub> != v<sub>j</sub></code></li>\n</ul>\n",
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"code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nbool* friendRequests(int n, int** restrictions, int restrictionsSize, int* restrictionsColSize, int** requests, int requestsSize, int* requestsColSize, int* returnSize) {\n \n}",
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"code": "# @param {Integer} n\n# @param {Integer[][]} restrictions\n# @param {Integer[][]} requests\n# @return {Boolean[]}\ndef friend_requests(n, restrictions, requests)\n \nend",
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"code": "impl Solution {\n pub fn friend_requests(n: i32, restrictions: Vec<Vec<i32>>, requests: Vec<Vec<i32>>) -> Vec<bool> {\n \n }\n}",
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"code": "-spec friend_requests(N :: integer(), Restrictions :: [[integer()]], Requests :: [[integer()]]) -> [boolean()].\nfriend_requests(N, Restrictions, Requests) ->\n .",
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"code": "defmodule Solution do\n @spec friend_requests(n :: integer, restrictions :: [[integer]], requests :: [[integer]]) :: [boolean]\n def friend_requests(n, restrictions, requests) do\n \n end\nend",
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"hints": [
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"For each request, we could loop through all restrictions. Can you think of doing a check-in close to O(1)?",
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"Could you use Union Find?"
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