mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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193 lines
18 KiB
JSON
193 lines
18 KiB
JSON
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"questionId": "2135",
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"title": "Maximum Number of Ways to Partition an Array",
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"content": "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> of length <code>n</code>. The number of ways to <strong>partition</strong> <code>nums</code> is the number of <code>pivot</code> indices that satisfy both conditions:</p>\n\n<ul>\n\t<li><code>1 <= pivot < n</code></li>\n\t<li><code>nums[0] + nums[1] + ... + nums[pivot - 1] == nums[pivot] + nums[pivot + 1] + ... + nums[n - 1]</code></li>\n</ul>\n\n<p>You are also given an integer <code>k</code>. You can choose to change the value of <strong>one</strong> element of <code>nums</code> to <code>k</code>, or to leave the array <strong>unchanged</strong>.</p>\n\n<p>Return <em>the <strong>maximum</strong> possible number of ways to <strong>partition</strong> </em><code>nums</code><em> to satisfy both conditions after changing <strong>at most</strong> one element</em>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,-1,2], k = 3\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> One optimal approach is to change nums[0] to k. The array becomes [<strong><u>3</u></strong>,-1,2].\nThere is one way to partition the array:\n- For pivot = 2, we have the partition [3,-1 | 2]: 3 + -1 == 2.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [0,0,0], k = 1\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> The optimal approach is to leave the array unchanged.\nThere are two ways to partition the array:\n- For pivot = 1, we have the partition [0 | 0,0]: 0 == 0 + 0.\n- For pivot = 2, we have the partition [0,0 | 0]: 0 + 0 == 0.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [22,4,-25,-20,-15,15,-16,7,19,-10,0,-13,-14], k = -33\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> One optimal approach is to change nums[2] to k. The array becomes [22,4,<u><strong>-33</strong></u>,-20,-15,15,-16,7,19,-10,0,-13,-14].\nThere are four ways to partition the array.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>2 <= n <= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>5</sup> <= k, nums[i] <= 10<sup>5</sup></code></li>\n</ul>\n",
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"A pivot point splits the array into equal prefix and suffix. If no change is made to the array, the goal is to find the number of pivot p such that prefix[p-1] == suffix[p].",
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"Consider how prefix and suffix will change when we change a number nums[i] to k.",
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"When sweeping through each element, can you find the total number of pivots where the difference of prefix and suffix happens to equal to the changes of k-nums[i]."
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