mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
42 lines
1.4 KiB
HTML
42 lines
1.4 KiB
HTML
<p>You are given an array of integers <code>nums</code>. You are also given an integer <code>original</code> which is the first number that needs to be searched for in <code>nums</code>.</p>
|
|
|
|
<p>You then do the following steps:</p>
|
|
|
|
<ol>
|
|
<li>If <code>original</code> is found in <code>nums</code>, <strong>multiply</strong> it by two (i.e., set <code>original = 2 * original</code>).</li>
|
|
<li>Otherwise, <strong>stop</strong> the process.</li>
|
|
<li><strong>Repeat</strong> this process with the new number as long as you keep finding the number.</li>
|
|
</ol>
|
|
|
|
<p>Return <em>the <strong>final</strong> value of </em><code>original</code>.</p>
|
|
|
|
<p> </p>
|
|
<p><strong class="example">Example 1:</strong></p>
|
|
|
|
<pre>
|
|
<strong>Input:</strong> nums = [5,3,6,1,12], original = 3
|
|
<strong>Output:</strong> 24
|
|
<strong>Explanation:</strong>
|
|
- 3 is found in nums. 3 is multiplied by 2 to obtain 6.
|
|
- 6 is found in nums. 6 is multiplied by 2 to obtain 12.
|
|
- 12 is found in nums. 12 is multiplied by 2 to obtain 24.
|
|
- 24 is not found in nums. Thus, 24 is returned.
|
|
</pre>
|
|
|
|
<p><strong class="example">Example 2:</strong></p>
|
|
|
|
<pre>
|
|
<strong>Input:</strong> nums = [2,7,9], original = 4
|
|
<strong>Output:</strong> 4
|
|
<strong>Explanation:</strong>
|
|
- 4 is not found in nums. Thus, 4 is returned.
|
|
</pre>
|
|
|
|
<p> </p>
|
|
<p><strong>Constraints:</strong></p>
|
|
|
|
<ul>
|
|
<li><code>1 <= nums.length <= 1000</code></li>
|
|
<li><code>1 <= nums[i], original <= 1000</code></li>
|
|
</ul>
|