mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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157 lines
19 KiB
JSON
157 lines
19 KiB
JSON
{
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"question": {
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"questionId": "1653",
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"questionFrontendId": "1530",
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"boundTopicId": null,
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"title": "Number of Good Leaf Nodes Pairs",
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"titleSlug": "number-of-good-leaf-nodes-pairs",
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"content": "<p>You are given the <code>root</code> of a binary tree and an integer <code>distance</code>. A pair of two different <strong>leaf</strong> nodes of a binary tree is said to be good if the length of <strong>the shortest path</strong> between them is less than or equal to <code>distance</code>.</p>\n\n<p>Return <em>the number of good leaf node pairs</em> in the tree.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/07/09/e1.jpg\" style=\"width: 250px; height: 250px;\" />\n<pre>\n<strong>Input:</strong> root = [1,2,3,null,4], distance = 3\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> The leaf nodes of the tree are 3 and 4 and the length of the shortest path between them is 3. This is the only good pair.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/07/09/e2.jpg\" style=\"width: 250px; height: 182px;\" />\n<pre>\n<strong>Input:</strong> root = [1,2,3,4,5,6,7], distance = 3\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> The good pairs are [4,5] and [6,7] with shortest path = 2. The pair [4,6] is not good because the length of ther shortest path between them is 4.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> root = [7,1,4,6,null,5,3,null,null,null,null,null,2], distance = 3\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> The only good pair is [2,5].\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the <code>tree</code> is in the range <code>[1, 2<sup>10</sup>].</code></li>\n\t<li><code>1 <= Node.val <= 100</code></li>\n\t<li><code>1 <= distance <= 10</code></li>\n</ul>\n",
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"difficulty": "Medium",
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"exampleTestcases": "[1,2,3,null,4]\n3\n[1,2,3,4,5,6,7]\n3\n[7,1,4,6,null,5,3,null,null,null,null,null,2]\n3",
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"categoryTitle": "Algorithms",
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"name": "Tree",
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"slug": "tree",
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"name": "Depth-First Search",
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"name": "Binary Tree",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode() : val(0), left(nullptr), right(nullptr) {}\n * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n int countPairs(TreeNode* root, int distance) {\n \n }\n};",
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{
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * int val;\n * TreeNode left;\n * TreeNode right;\n * TreeNode() {}\n * TreeNode(int val) { this.val = val; }\n * TreeNode(int val, TreeNode left, TreeNode right) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\nclass Solution {\n public int countPairs(TreeNode root, int distance) {\n \n }\n}",
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"lang": "Python",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution(object):\n def countPairs(self, root, distance):\n \"\"\"\n :type root: TreeNode\n :type distance: int\n :rtype: int\n \"\"\"\n ",
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"code": "# Definition for a binary tree node.\n# class TreeNode:\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution:\n def countPairs(self, root: TreeNode, distance: int) -> int:\n ",
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"lang": "C",
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"langSlug": "c",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * struct TreeNode *left;\n * struct TreeNode *right;\n * };\n */\n\n\nint countPairs(struct TreeNode* root, int distance){\n\n}",
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"langSlug": "csharp",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public int CountPairs(TreeNode root, int distance) {\n \n }\n}",
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"__typename": "CodeSnippetNode"
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"lang": "JavaScript",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @param {number} distance\n * @return {number}\n */\nvar countPairs = function(root, distance) {\n \n};",
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"lang": "Ruby",
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"langSlug": "ruby",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @param {Integer} distance\n# @return {Integer}\ndef count_pairs(root, distance)\n \nend",
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{
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"lang": "Swift",
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"langSlug": "swift",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func countPairs(_ root: TreeNode?, _ distance: Int) -> Int {\n \n }\n}",
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"__typename": "CodeSnippetNode"
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},
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{
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"lang": "Go",
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"langSlug": "golang",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc countPairs(root *TreeNode, distance int) int {\n \n}",
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"lang": "Scala",
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"langSlug": "scala",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def countPairs(root: TreeNode, distance: Int): Int = {\n \n }\n}",
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"lang": "Kotlin",
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"langSlug": "kotlin",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun countPairs(root: TreeNode?, distance: Int): Int {\n \n }\n}",
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"__typename": "CodeSnippetNode"
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{
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"lang": "Rust",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n// \n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn count_pairs(root: Option<Rc<RefCell<TreeNode>>>, distance: i32) -> i32 {\n \n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @param Integer $distance\n * @return Integer\n */\n function countPairs($root, $distance) {\n \n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction countPairs(root: TreeNode | null, distance: number): number {\n\n};",
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"hints": [
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"Start DFS from each leaf node. stop the DFS when the number of steps done > distance.",
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"If you reach another leaf node within distance steps, add 1 to the answer.",
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"Note that all pairs will be counted twice so divide the answer by 2."
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],
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"sampleTestCase": "[1,2,3,null,4]\n3",
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