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leetcode-problemset/leetcode-cn/problem (English)/元素和小于等于阈值的正方形的最大边长(English) [maximum-side-length-of-a-square-with-sum-less-than-or-equal-to-threshold].html
2022-03-29 12:43:11 +08:00

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<p>Given a <code>m x n</code> matrix <code>mat</code> and an integer <code>threshold</code>, return <em>the maximum side-length of a square with a sum less than or equal to </em><code>threshold</code><em> or return </em><code>0</code><em> if there is no such square</em>.</p>
<p>&nbsp;</p>
<p><strong>Example 1:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2019/12/05/e1.png" style="width: 335px; height: 186px;" />
<pre>
<strong>Input:</strong> mat = [[1,1,3,2,4,3,2],[1,1,3,2,4,3,2],[1,1,3,2,4,3,2]], threshold = 4
<strong>Output:</strong> 2
<strong>Explanation:</strong> The maximum side length of square with sum less than 4 is 2 as shown.
</pre>
<p><strong>Example 2:</strong></p>
<pre>
<strong>Input:</strong> mat = [[2,2,2,2,2],[2,2,2,2,2],[2,2,2,2,2],[2,2,2,2,2],[2,2,2,2,2]], threshold = 1
<strong>Output:</strong> 0
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>m == mat.length</code></li>
<li><code>n == mat[i].length</code></li>
<li><code>1 &lt;= m, n &lt;= 300</code></li>
<li><code>0 &lt;= mat[i][j] &lt;= 10<sup>4</sup></code></li>
<li><code>0 &lt;= threshold &lt;= 10<sup>5</sup></code></li>
</ul>