1
0
mirror of https://gitee.com/coder-xiaomo/leetcode-problemset synced 2025-01-10 18:48:13 +08:00
Code Issues Projects Releases Wiki Activity GitHub Gitee
leetcode-problemset/leetcode-cn/problem (English)/判断通过操作能否让字符串相等 I(English) [check-if-strings-can-be-made-equal-with-operations-i].html
2023-09-09 15:37:57 +08:00

37 lines
1.5 KiB
HTML

<p>You are given two strings <code>s1</code> and <code>s2</code>, both of length <code>4</code>, consisting of <strong>lowercase</strong> English letters.</p>
<p>You can apply the following operation on any of the two strings <strong>any</strong> number of times:</p>
<ul>
<li>Choose any two indices <code>i</code> and <code>j</code> such that <code>j - i = 2</code>, then <strong>swap</strong> the two characters at those indices in the string.</li>
</ul>
<p>Return <code>true</code><em> if you can make the strings </em><code>s1</code><em> and </em><code>s2</code><em> equal, and </em><code>false</code><em> otherwise</em>.</p>
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre>
<strong>Input:</strong> s1 = &quot;abcd&quot;, s2 = &quot;cdab&quot;
<strong>Output:</strong> true
<strong>Explanation:</strong> We can do the following operations on s1:
- Choose the indices i = 0, j = 2. The resulting string is s1 = &quot;cbad&quot;.
- Choose the indices i = 1, j = 3. The resulting string is s1 = &quot;cdab&quot; = s2.
</pre>
<p><strong class="example">Example 2:</strong></p>
<pre>
<strong>Input:</strong> s1 = &quot;abcd&quot;, s2 = &quot;dacb&quot;
<strong>Output:</strong> false
<strong>Explanation:</strong> It is not possible to make the two strings equal.
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>s1.length == s2.length == 4</code></li>
<li><code>s1</code> and <code>s2</code> consist only of lowercase English letters.</li>
</ul>