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30 lines
1.2 KiB
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30 lines
1.2 KiB
HTML
<p>Given a circular integer array <code>nums</code> (i.e., the next element of <code>nums[nums.length - 1]</code> is <code>nums[0]</code>), return <em>the <strong>next greater number</strong> for every element in</em> <code>nums</code>.</p>
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<p>The <strong>next greater number</strong> of a number <code>x</code> is the first greater number to its traversing-order next in the array, which means you could search circularly to find its next greater number. If it doesn't exist, return <code>-1</code> for this number.</p>
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<p> </p>
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<p><strong class="example">Example 1:</strong></p>
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<pre>
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<strong>Input:</strong> nums = [1,2,1]
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<strong>Output:</strong> [2,-1,2]
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Explanation: The first 1's next greater number is 2;
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The number 2 can't find next greater number.
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The second 1's next greater number needs to search circularly, which is also 2.
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</pre>
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<p><strong class="example">Example 2:</strong></p>
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<pre>
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<strong>Input:</strong> nums = [1,2,3,4,3]
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<strong>Output:</strong> [2,3,4,-1,4]
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</pre>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>1 <= nums.length <= 10<sup>4</sup></code></li>
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<li><code>-10<sup>9</sup> <= nums[i] <= 10<sup>9</sup></code></li>
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</ul>
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